Jump to content

Recommended Posts

Posted

I had nothing to do, so I made sth like this :P

Done in 2 hours. I`m not sure about the way the speed is counted but I think it`s correct :lmao:

Say what you think about it :(

haha, i like it. but it doesn't figure speed right for diagonals. one sec, i'm gonna test a re-write just 'cause i think this is neat....
Posted (edited)

haha, i like it. but it doesn't figure speed right for diagonals. one sec, i'm gonna test a re-write just 'cause i think this is neat....

i think your formulas are off... maybe...

if i remember right, the length of a line can be determined with...

sqrt((y2-y1)(y2-y1)+(x2-x1)(x2-x1))

and that's just based off of a squared + b squared = c squared...

so you're figuring the squared lenths of the base and height of the triangle with the (y2-y1)(y2-y1)+(x2-x1)(x2-x1) then just take the squareroot of that number for the length of the hypotenuse (spelling?)

Edited by cameronsdad

Create an account or sign in to comment

You need to be a member in order to leave a comment

Create an account

Sign up for a new account in our community. It's easy!

Register a new account

Sign in

Already have an account? Sign in here.

Sign In Now
×
×
  • Create New...