#IND?

[lopolop]

what does #IND mean...

i am making a quadratic calculator and there is a formula i put in it seems to work i will do more tests to check but it looks all right...

if you dont no the formula to find the solutions of a quadratic/parabola is

[-$B +- Sqrt( $B^2-4*$A*$B)]/2*$A

for some reason i most of the time get a answer of 1.#IND, 1.#IND

i dont understand...

[Jos]

what does #IND mean...

i am making a quadratic calculator and there is a formula i put in it seems to work i will do more tests to check but it looks all right...

if you dont no the formula to find the solutions of a quadratic/parabola is

[-$B +- Sqrt( $B^2-4*$A*$B)]/2*$A

for some reason i most of the time get a answer of 1.#IND, 1.#IND

i dont understand...

#IND means division by zero

[cdkid]

did a quick search in the hepfile and found these

under Log function:

Return values:

Failure: Tends to return -1.#IND for non-positive parameters.

under the ACos function:

Remarks:

ACos(x) is mathematically defined only for -1 < x < 1, so ACos tends to return -1.#IND for other values of x.

Under the ASin function:

Remarks:

ASin(x) is mathematically defined only for -1 < x < 1, so ASin tends to return -1.#IND for other values of x.

Under the Mod function:

Return Values:

Failure: Returns -1.#IND if the divisor is zero.

--hope this helps

~cdkid

Edited February 9, 2006 by cdkid

[lopolop]

ok i think it returns that when there are no solutions.

Thanks!

[MSLx Fanboy]

You need to do error checking before calculating it. Pardon my C/AutoIt, I haven't touched an au3 file in days

;(-b +- sqrt(b^2-4ac))/(2a)
if (a == 0) break; //division by zero
discriminant = b^2-4ac
if (discriminant < 0) //imaginary numbers
break;
if (discriminant == 0) //one real solution
answer = -b/(2a)
if (discriminant > 0){ //two real solutions
   Dim answer[2]
   answer[0] = (-b+sqrt(discriminant))/(2a)
   answer[1] = (-b-sqrt(discriminant))/(2a)
}

Hope you understand

Edited February 10, 2006 by MSLx Fanboy