Stop loop problem

[Champak]

I have message box inside an "If" statement where I have a "yes" or "no" question. Upon "no" the function is suppose to stop...but the GUI should remain open. If I put "exit" --- which is the only way I know how to stop a function --- the GUI exits. If I put in "EndLoop", it wont allow it. How do I do this?

Edit:

I solved the problem a different way, but am still interested in a specific solution for this if there is one.

Edited May 23, 2006 by Champak

[MHz]

Use Return to exit from a function.

[Gyzmok]

example :

Func _check_msgbox_overwrite($file,$dest,$type)
    if msgbox(1+256+48,"The destination is newer","Do you want to replace the newer file :" _
       &@lf&@lf&_gettime($dest&$type&$fname)&" "&$dest&$type&$fname&" "&@lf&@lf& _
       "by this older file ?"&@lf&@lf&_gettime($file)&" "&$file) = 1 then
        return 1
    Else
        return 0
    EndIf
EndFunc;==>_check_msgbox_overwrite

Edited June 2, 2006 by Gyzmok

[Champak]

Thanks. Now instead of doing whay you did Gyzmok, I just put ";" to continue through for yes and "Return" for no. Is there a reason you did return 1 and 0? Or is that just "proper" coding?

[MHz]

Gyzmok is returning a boolean condition with the example. 0 is a false condition, and not 0 is true. Same concept can be regarded with strings as "" is a false condition, and "something" is a true condition. The keywords If and Then will test the condition. If you expect a string return, then the latter could be chosen as a suitable return value to use.

This may help with some understanding:

_Check( _0() )
_Check( _1() )
_Check( _2() )
_Check( _3() )

Func _Check($condition)
    ; Check the $condition
    If $condition Then
        MsgBox(0, $condition, 'True condition')
    Else
        MsgBox(0, $condition, 'False condition')
    EndIf
EndFunc

Func _0()
    ; Return a false numerical condition
    Return 0
EndFunc

Func _1()
    ; Return a true numerical condition
    Return 1
EndFunc

Func _2()
    ; Return a false string condition
    Return ""
EndFunc

Func _3()
    ; Return a true string condition
    Return "string"
EndFunc