trids Posted January 5, 2004 Posted January 5, 2004 I can't seem to find mention in the help file of the syntax for raising a number to the power of another.. ;expecting 100 here .. msgbox (4096,"", 10 ^ 2) ;returns ERROR at "^" msgbox (4096,"", 10 ** 2) ;returns 0 I'm sure I must be missing something obvious
Administrators Jon Posted January 5, 2004 Administrators Posted January 5, 2004 You are. You can't. Pow() will be in 3.0.85 though.
trids Posted January 5, 2004 Author Posted January 5, 2004 Thanks Jon ... just curious though: any reason it needs to be a function, as opposed to an operator?
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