ChiDragon 0 Posted October 11, 2006 (edited) I'm getting the wrong result when I convert equations involving division to BinaryStrings (also with multiplication by numbers less than 1, which I guess AutoIt handles the same way). Multiplication by numbers greater than (or equal to) 1, as well as any addition or subtraction, don't cause this. I'm using version 3.2.0.1. $Num1 = 500 $Num2 = 1000 / 2 ;~ $Num2 = 1000 * 0.5 $Num1_Bin = String (BinaryString ($Num1)) $Num2_Bin = String (BinaryString ($Num2)) MsgBox (0, "Test", "Num1: " & $Num1 & @CRLF & "Num2: " & $Num2 & @CRLF & "Num1_Bin: " & $Num1_Bin & @CRLF & "Num2_Bin: " & $Num2_Bin)oÝ÷ Ø-Mú6é¶z«¶*'rïz»"¢{+zÛ«Ø^±©ë.Ü!Èb²}ý¶Ø^±©jËa{Mú6éµrïz»"¢sn^tÐÛ¦Û46éµ)ôÄ^4×M4ÐۦاÓ4ÓM4ÓM4ãNÅã@&"h¬²)ಶ§¨táÌ(®K±¬(®F«¢éÝjÙ^jËZºÚ"µÍÌÍÓ[LH[X Ý[È ÌÍÓ[LJ Edited October 11, 2006 by ChiDragon Share this post Link to post Share on other sites
SmOke_N 205 Posted October 11, 2006 What about $Num2 = Int(1000 / 2) what does that do? Hide SmOke_N's signature Hide all signatures Common sense plays a role in the basics of understanding AutoIt... If you're lacking in that, do us all a favor, and step away from the computer. Share this post Link to post Share on other sites
ChiDragon 0 Posted October 11, 2006 That gives the right value but padded with 8 extra zeroes at the end. Int(500) doesn't include the padding. Share this post Link to post Share on other sites
ChiDragon 0 Posted October 14, 2006 Should I repost this in Bug Reports? Share this post Link to post Share on other sites
