Is there any way to get the filename from the variable pointing to the opened file?

[Denis]

Is there any way to get the filename from the variable pointing to the opened file?

: $file=fileopen("something.txt")

How can I get the "something.txt" from $file ?

Should I use another variable to keep the name of the opened file?

: $filename="something.txt"

: $file=fileopen($filename,0)

[PaulIA]

$filename="something.txt"
$file=fileopen($filename,0)

This is probably the most intuitive way to do this. That way, if you need to display the file name somewhere in your program, you're not dealing with a hard coded string.