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Denis

Is there any way to get the filename from the variable pointing to the opened file?

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Is there any way to get the filename from the variable pointing to the opened file?

: $file=fileopen("something.txt")

How can I get the "something.txt" from $file ?

Should I use another variable to keep the name of the opened file?

: $filename="something.txt"

: $file=fileopen($filename,0)

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