How to read words in a editbox..

[bigassmuffin]

Func _Translate
Local $quite = 0
    If $option = "English to code" then
        If $text = "hello" then
            GUICtrlDelete( $Edit2 )
            $Edit2 = GUICtrlCreateEdit("xz4", 8, 184, 305, 97)
        EndIf
    ElseIf $option = "code to English" then
        If $text = "xz4" then
            GUICtrlDelete( $Edit2 )
            $Edit2 = GUICtrlCreateEdit("hello", 8, 184, 305, 97)
        EndIf
    EndIf
EndFunc

I put random example in there for a better understanding.

The problem is, if I type for example, "Hello Fred", it will not translate, only if the "Hello" is alone.

So in vb I know the commands are len(variable) and mid(variable, start, leanth)

How do i do that in autoit?

or any other way...?

As always, I REALLY appreciate your time and support,

THANKS!

BigAssmuffin

[SmOke_N]

1. GUICtrl*Function + Read = GUICtrlRead()

2. String questions would have been answered had you cracked open the help file I don't know VB, but I would bet that:

len(variable) = StringLen($variable)

mid(variable, start, length) = StringMid($variable, $nStart, $nLen)

[bigassmuffin]

1. GUICtrl*Function + Read = GUICtrlRead()

2. String questions would have been answered had you cracked open the help file I don't know VB, but I would bet that:

len(variable) = StringLen($variable)

mid(variable, start, length) = StringMid($variable, $nStart, $nLen)

Ya, i jsut figured out the leanth one, is there a way though to check for an entire word, instead of looking letter by letter?

Because with the stringmid command I would have to do:

If StringMid($variable, $nStart, 1) = "H" or If StringMid($variable, $nStart, 1) = "h" then
If StringMid($variable, $nStart+1, 1) = "E" or If StringMid($variable, $nStart+1, 1) = "e" then
If StringMid($variable, $nStart+2, 1) = "L" or If StringMid($variable, $nStart+2, 1) = "l" then
If StringMid($variable, $nStart+3, 1) = "L" or If StringMid($variable, $nStart+3, 1) = "l" then
If StringMid($variable, $nStart+4, 1) = "O" or If StringMid($variable, $nStart+4, 1) = "o" then
GUICtrlDelete( $Edit2 )
$Edit2 = GUICtrlCreateEdit("howdy", 8, 184, 305, 97)
EndIf
EndIf
EndIf
EndIf
EndIf

I think theres an easier way...?

Edited January 22, 2007 by bigassmuffin

[SmOke_N]

Ya, i jsut figured out the leanth one, is there a way though to check for an entire word, instead of looking letter by letter?

Because with the stringmid command I would have to do:

If StringMid($variable, $nStart, 1) = "H" or If StringMid($variable, $nStart, 1) = "h" then
If StringMid($variable, $nStart+1, 1) = "E" or If StringMid($variable, $nStart+1, 1) = "e" then
If StringMid($variable, $nStart+2, 1) = "L" or If StringMid($variable, $nStart+2, 1) = "l" then
If StringMid($variable, $nStart+3, 1) = "L" or If StringMid($variable, $nStart+3, 1) = "l" then
If StringMid($variable, $nStart+4, 1) = "O" or If StringMid($variable, $nStart+4, 1) = "o" then
GUICtrlDelete( $Edit2 )
$Edit2 = GUICtrlCreateEdit("howdy", 8, 184, 305, 97)
EndIf
EndIf
EndIf
EndIf
EndIf

Note: == would be case sensitive, just using = is not case sensitive.

Edited January 22, 2007 by SmOke_N

[bigassmuffin]

If you gave an actual "working" example instead of sporadic code, maybe I could show you something... or else, all I can suggest is StringRegExp() and you figure out how to use it.

Edit:

Or ... looking at your code:

If StringLeft($variable, 4) = 'hello' Then

Note: == would be case sensitive, just using = is not case sensitive.

Ill try this, thanks!