FileOpenDialog

[butji]

how come this work

$message = "Choose game exe"
$path2 = FileOpenDialog($message, @ProgramFilesDir & "\", "All (*.*)", 1 + 4)
msgbox( 1, "", $path2 )

[Mast3rpyr0]

there is another way to write to ini files. INIwrite()

$message = "Choose game exe"
$path2 = FileOpenDialog($message, @ProgramFilesDir & "\", "All (*.*)", 1 + 4)
IniWrite("games.ini", "games", "1", $path2)

your INI would be:

[games]
1=PathFromProgram

[butji]

yea but that doesnt work either and i would rather use filewriteline

[Mast3rpyr0]

if its an ini dont use filewriteline, it wont let you use the ini correctly if you dont. be sure you have a games.ini with

[games]

1=

already in it and in the same folder as your script

[PsaltyDS]

Are you sure it's NOT working? When FileOpenDialog() is done, the directory of the file selected becomes the working directory. Since you didn't provide a path for "games.ini" it will be created\written in the same folder as the selected file, not the script directory.

$message = "Choose game exe"
MsgBox(64, "Debug (before)", "@WorkingDir = " & @WorkingDir & @LF)
$path2 = FileOpenDialog($message, @ProgramFilesDir & "\", "All (*.*)", 1 + 4)
MsgBox(64, "Debug (after)", "$path2 = " & $path2 & @CRLF & _
        "@WorkingDir = " & @WorkingDir)

Edited June 16, 2007 by PsaltyDS

[Mast3rpyr0]

i think that the program i made is what your trying to do. look through my code if you get stuck. Link's in my sig.