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Posted (edited)

Explain better. If you dont know the file name, where are the file ?

How do you know the file that you want to know the name ?

Dim $file
Dim $tmp

$file="test.txt"

$tmp=fileread($file)

msgbox(0,"test","This are file contents"&$tmp&" and this are the file name "&$file)
Edited by Kram3r

To all the Devs: Thkx for AutoIt To all Mods: Thkx for the quality forum

Posted

Explain better. If you dont know the file name, where are the file ?

How do you know the file that you want to know the name ?

Files are created from the run of an application. File name's format is already specified inside the program but the files' names vary depending on the workload. So, I would like to check the names (of the files that are generated after the program's run) to see they are in expected format.
Posted (edited)

Dim $file
Dim $tmp

$file="test.txt"

$tmp=fileread($file)

msgbox(0,"test","This are file contents"&$tmp&" and this are the file name "&$file)
It returns the file name as "1", while it's actually "test.txt" Edited by JustDoIt
Posted (edited)

You can use for your case:

_FileListToArray ()

Description: Lists files and\or folders in a specified path (Similar to using Dir with the /B Switch)

PS: In my environment the above example returns "test.txt" for the file name.

Edited by Kram3r

To all the Devs: Thkx for AutoIt To all Mods: Thkx for the quality forum

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