sequencing..... for & next

[Aceguy]

how can i calulate this squence

1=a

2=b

3=c

4=d

5=e

6=f

7=g

8=h

9=a

10=b

11=c

12=d

ect.

first number carrys on, second number only goes to h, then back to a.

also.... if i know the first number of say 263, what second letter be(a to h).?

you help is much appreciated.

Edited January 7, 2008 by Aceguy

[star2]

I didn't get it can u explain?

EDIT

I'm becoming too slow !!

Edited January 7, 2008 by star2

[Jex]

$Find = Find(55)
$Find2 = Find(55, 2)
MsgBox("", "", "55. result : " & $Find & @CRLF & "All results until 55 : " & $Find2)

Func Find($Num, $Type = 1)
    Local $Count = 0, $Var
    For $i = 1 To $Num
        $Count += 1
        If $Count = 9 Then $Count = 1
        If $Type = 1 Then
            $Var = Chr(96 + $Count)
        Else
            $Var &= Chr(96 + $Count)
        EndIf
    Next
    Return $Var
EndFunc

Edited January 7, 2008 by Jex

[Aceguy]

SUPERB, thanksso much

[Xandl]

Hello,

maybe Mod() can help you:

Global $a[8] = ['h','a','b','c','d','e','f','g']

$i=4
ConsoleWrite($a[Mod($i,8)]&@LF)
$i=8
ConsoleWrite($a[Mod($i,8)]&@LF)
$i=12
ConsoleWrite($a[Mod($i,8)]&@LF)
$i=20
ConsoleWrite($a[Mod($i,8)]&@LF)
$i=263
ConsoleWrite($a[Mod($i,8)]&@LF)

ciao

Xandl

[Jex]

if i know the first number of say 263, what second letter be(a to h).?

For your second question :

$MyNumber = 263
$Find = Find($MyNumber + 1)
MsgBox("", "", $Find)

Func Find($Num, $Type = 1)
    Local $Count = 0, $Var
    For $i = 1 To $Num
        $Count += 1
        If $Count = 9 Then $Count = 1
        If $Type = 1 Then
            $Var = Chr(96 + $Count)
        Else
            $Var &= Chr(96 + $Count)
        EndIf
    Next
    Return $Var
EndFuncoÝ÷ Ú«¨µáÞZ&k&Þ2jx^¨»ú®¢×¢êì¢[­ÛzÛ^®ØZlv÷öÙ'£hÂj~éܶ*'ÂäxºÚ"µÍÌÍÕ[YH[Y[]

BÌÍÑ[H[
ÊBÙÐÞ
    ][ÝÉ][ÝË    ][ÝÉ][ÝË    ÌÍÑ[ [È ][ÝÈ  ][ÝÈ  [È[YY  ÌÍÕ[YJBÌÍÕ[YH[Y[]

BÌÍÑ[H[ÊBÙÐÞ
    ][ÝÉ][ÝË    ][ÝÉ][ÝË    ÌÍÑ[ [È ][ÝÈ  ][ÝÈ  [È[YY  ÌÍÕ[YJB[È[
    ÌÍÓ[K    ÌÍÕHHJBSØØ[    ÌÍÐÛÝ[H    ÌÍÕQÜ   ÌÍÚHHHÈ ÌÍÓ[BBIÌÍÐÛÝ[
ÏHBBRY ÌÍÐÛÝ[HH[  ÌÍÐÛÝ[HBBRY    ÌÍÕHHH[BBIÌÍÕHÚM
È  ÌÍÐÛÝ[
BBQ[ÙBBBIÌÍÕ    [ÏHÚM
È  ÌÍÐÛÝ[
BBQ[YS^T]   ÌÍÕ[[ÈÏOIÝÑ[[È[ ÌÍÓ[JBSØØ[ ÌÍÐ^VÎHHÉÌÎNÚ   ÌÎNË ÌÎNØIÌÎNË ÌÎNØÌÎNË  ÌÎNØÉÌÎNË    ÌÎNÙ ÌÎNË ÌÎNÙIÌÎNË ÌÎNÙÌÎNË  ÌÎNÙÉÌÎN×BT] ÌÍÐ^VÓ[Ù
    ÌÍÓ[K
WB[[ÈÏOIÝÑ[

For test calculation speeds and your function more fast

Edited January 7, 2008 by Jex

[Xandl]

Hello,

I don't know how mod function working.

Mod returns the remainder of a division. That sounds complicated.

But (x mod y) just returns a value between 0 and y-1, this sounds useful for arrays.

So we put the last item 'h' into array element 0, to not let it be empty.

Whichever value comes from x, mod will always return a value between 0 and y-1.

ciao

Xandl

[DirtDBaK]

it's like back in forth grade, you know the 'remainder' lol like 4 goes into 14, 3 times with a remainder of 2...

Hope that helps

[weaponx]

Long division