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oliver369

Obtaining process path under 64bit editions of Windows

2 posts in this topic

#1 ·  Posted (edited)

Hi,

I am trying to create a function that lists out processes with their full paths, after quite a bit of research I have found what I want. Here is the code:

Func _ProcessGetLocation($iPID)
    Local $aProc = DllCall('kernel32.dll', 'hwnd', 'OpenProcess', 'int', BitOR(0x0400, 0x0010), 'int', 0, 'int', $iPID)
    If $aProc[0] = 0 Then Return SetError(1, 0, '')
    Local $vStruct = DllStructCreate('int[1024]')
    DllCall('psapi.dll', 'int', 'EnumProcessModules', 'hwnd', $aProc[0], 'ptr', DllStructGetPtr($vStruct), 'int', DllStructGetSize($vStruct), 'int*', 0)
    Local $aReturn = DllCall('psapi.dll', 'int', 'GetModuleFileNameEx', 'hwnd', $aProc[0], 'int', DllStructGetData($vStruct, 1), 'str', '', 'int', 2048)
    If StringLen($aReturn[3]) = 0 Then Return SetError(2, 0, '')
    Return $aReturn[3]
EndFunc

This works fine under 32bit editions of Windows (XP+Vista) but not under 64bit editions. Does anybody know a workaround/solution to this problem?

Edited by oliver369

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Answered my own question. But here is the answer for future reference: when compiling use the x64 option :D

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