Swift Posted April 3, 2008 Posted April 3, 2008 I was thinking StringFormat() or StringTrimLeft() but, StringTrimLeft() Wouldn't be accurate, if you took more than 99 seconds. I just need to display the seconds, and 2 digits after it. So it shows like this: $Time = TimerInit() Sleep(15000) MsgBox(0, "", TimerDiff($Time)) And, I need that to display 15.00 If anyone could help with this topic, thanks. I wish I could learn StringFormat() It's complicated though.
monoceres Posted April 3, 2008 Posted April 3, 2008 (edited) You won't here's a perfectly good example without it: $timer=TimerInit() Sleep(15000) $seconds=Round(TimerDiff($timer)/1000,2) If IsInt($seconds) Then $seconds&=".00" MsgBox(0,"",$seconds) Simple and effective Edited April 3, 2008 by monoceres Broken link? PM me and I'll send you the file!
MDCT Posted April 3, 2008 Posted April 3, 2008 I believe this could too: $Time = TimerInit() Sleep(1500) $Time=TimerDiff($Time)/1000 $Show =StringFormat ("%.2f",$Time) MsgBox(0, "", $Show)
PsaltyDS Posted April 3, 2008 Posted April 3, 2008 You won't here's a perfectly good example without it: $timer=TimerInit() Sleep(15000) $seconds=Round(TimerDiff($timer)/1000,2) If IsInt($seconds) Then $seconds&=".00" MsgBox(0,"",$seconds)oÝ÷ Ù(¦¦W×}ç-÷¿ªê-y&¦zØbî¶W¶)àJÚâh®fva{ +«¢+ØÀÌØíÑ¥µÈõQ¥µÉ%¹¥Ð ¤)M±À ÄÔÀÀÀ¤(ÀÌØíͽ¹ÌôMÑÉ¥¹½ÉµÐ ÅÕ½Ðì¸ÉÅÕ½Ðì°Q¥µÉ¥ ÀÌØíÑ¥µÈ¤¼ÄÀÀÀ¤)5Í ½à À°ÅÕ½ÐìÅÕ½Ðì°ÀÌØíͽ¹Ì¤ Valuater's AutoIt 1-2-3, Class... Is now in Session!For those who want somebody to write the script for them: RentACoder"Any technology distinguishable from magic is insufficiently advanced." -- Geek's corollary to Clarke's law
Swift Posted April 3, 2008 Author Posted April 3, 2008 Whoa! Thanks Guys! Thanks so much! So Fast, and everything! It works perfectly now! Yes! Thanks!!
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