Running a .BAT file

[CygnusX1]

Hello All,

I have a script that I'm trying to call a .BAT file from

Run("file_compare.bat", "c:\program files\program name\root dir")

The help says to use a file name then the working directory, which is what I'm doing.

I have downloaded the latest release of AutoIt

For what it's worth, the .BAT runs ImageMagick and compares a directory full of images. I can get the .BAT file to run from the CMD window or double clicking on the file in the directory.

Any ideas why this wouldn't be working?

Thanks

Cygnus

[LongBowNZ]

I think you might need ShellExecute() with a .bat file.

[CygnusX1]

Thank you, ShellExecute worked!

ShellExecute("file_compare", "", "C:\Program Files\program name\root dir")

Cygnus

[PsaltyDS]

You may need to path out the executable:

$sDir = "c:\program files\program name\root dir"
$sFile = "file_compare.bat"
Run($sDir & "\" & $sFile, $sDir, @SW_SHOW)

Edit: Well that's what I get for not checking on replies already posted:

Thank you, ShellExecute worked!

ShellExecute("file_compare", "", "C:\Program Files\program name\root dir")

Cygnus

Edited June 19, 2008 by PsaltyDS

[LongBowNZ]

Edit: Well that's what I get for not checking on replies already posted:

Happens to me all the time.