icon button in GUI?

[phew]

hey,

i created a little gui and added an icon via guictrlcreateicon() to it. now i want to interact with this icon, ie. when i click on the icon then should pop up some msgbox(). how do i do that?

well my icon is a folder and i'd need it for FileOpenDialogue() but i have no clue how to detect a mouseclick that hit it!

greetings

[ProgAndy]

Like a normal button With GUIGetMsg()

[phew]

Like a normal button With GUIGetMsg()

is there no waii to use an icon/pic as button instead of creating a button by guictrlcreatebutton()?

[ProgAndy]

Cant't you read ^^ LIKE a button ... So you can use Icons:

$pic = GUICtrlCreateIcon...

$msg = GUIGetMsg()

If $msg = $pic Then ...

[JFee]

You're overlooking what Andy said. You can detect a mouse click on ANY control the same way you would a button.

$Icon = guictrlcreateicon(...)

$msg = guigetmsg()

switch $msg
    case $Icon
      ; CODE HERE
endswitch

EDIT: Darn, beat me to it

Edited August 1, 2008 by JFee

[phew]

Cant't you read ^^ LIKE a button ... So you can use Icons:

$pic = GUICtrlCreateIcon...

$msg = GUIGetMsg()

If $msg = $pic Then ...

ahhhh sorry my bad!

nuff thanks