Select File Name In File Path

[DeeRiee]

I'm newbie here, and i want to ask about how to select the file name in file path?

example: d:\document\autoit.exe

How to select only the autoit.exe

Please tell me script that can select file name in any path and file name

[dbzfanatic]

$path = "d:\document\autoit.exe"
$array = StringSplit($path,"\")
$name = $array[$array[0]]
MsgBox(64,"Name",$name)

[smashly]

Another way:

$sPath = "d:\document\autoit.exe"
$sFileName = StringTrimLeft($sPath, StringInStr($sPath, "\", 0, -1))
ConsoleWrite($sFileName & @LF)

[AdmiralAlkex]

There is also _PathSplit(), but it may be excessive depending on what you are doing

[rasim]

More solutions:

$path = "d:\document\autoit.exe"
$file = StringRegExpReplace($path, "^.*\\", "")
ConsoleWrite($file & @LF)

[SmOke_N]

More solutions:

$path = "d:\document\autoit.exe"
$file = StringRegExpReplace($path, "^.*\\", "")
ConsoleWrite($file & @LF)

Ha, nice... I do that much more complicated.

[DeeRiee]

$path = "d:\document\autoit.exe"
$array = StringSplit($path,"\")
$name = $array[$array[0]]
MsgBox(64,"Name",$name)

Thanks, It's Work

[DeeRiee]

Another way:

$sPath = "d:\document\autoit.exe"
$sFileName = StringTrimLeft($sPath, StringInStr($sPath, "\", 0, -1))
ConsoleWrite($sFileName & @LF)

Working, Thanks

[DeeRiee]

THANK'S ALL FOR HELPING ME!!!!!

[euverve]

Thanks for the share guys...