Quick hex question

[Gar]

I can't really figure out how to do this in AutoIT, any help would be appreciated. How do I detect a certain digit in a hex number, like the 5 in 0x0050, and how do I then change it to a 3, like 0x0030?

Pseudocode:

Func ThirdDigitTo3($hex)

if {third digit of $hex) = 5 Then

...{change third digit of $hex to 3}

endif

Endfunc

Thanks!

[enaiman]

$a = 0x0050
$b = String(Hex($a, 4))

$split = StringSplit($b, "")

If $split[3] = 5 Then $split[3] = 3
$new = "0x"&$split[1]&$split[2]&$split[3]&$split[4]
$new_nbr = Hex($new, 4)

MsgBox(0, "new number", $new_nbr)

Can be refined or made simpler but I don't have much time now ...

[Malkey]

I can't really figure out how to do this in AutoIT, any help would be appreciated. How do I detect a certain digit in a hex number, like the 5 in 0x0050, and how do I then change it to a 3, like 0x0030?

Pseudocode:

Func ThirdDigitTo3($hex)

if {third digit of $hex) = 5 Then

...{change third digit of $hex to 3}

endif

Endfunc

Thanks!

Try this

$hex = 0x40550
MsgBox(0, "", SecondDigitTo3($hex))

Func SecondDigitTo3($hex)
    If BitAND($hex, 0x000000F0) = 0x00000050 Then
        $hex = BitOR(BitAND($hex, 0xFFFFFF0F), 0x00000030)
    EndIf
    Return Hex($hex)
EndFunc   ;==>ThirdDigitTo3

[therks]

Just subtract 32 (0x20)

[rasim]

RobSaunders

Just subtract 32 (0x20)

Yes:

$hex = 0x00000050
MsgBox(0, "", _Subtract($hex, 0x00000020))

Func _Subtract($sHex, $sSubtrahend)
    Local $iResult = ($sHex - $sSubtrahend)
    Return "0x" & Hex($iResult)
EndFunc   ;==>_Subtract

When the hex string are passed to a function it automatically convert to a decimal value

[rasim]

Hubertus

StringInStr()
StringReplace()
RegExpReplace()

?

[martin]

When the hex string are passed to a function it automatically convert to a decimal value

??

When a hex value is passed to a function that value is passed. Whether it is decimal or hex is a question of how you want to deal with it in the function, isn't it?

When a string is pased to a function that string is passed.

[rasim]

??

When a hex value is passed to a function that value is passed. Whether it is decimal or hex is a question of how you want to deal with it in the function, isn't it?

When a string is pased to a function that string is passed.

I know, see the example:

MsgBox(0, "Decimal", Dec("0000FFFF")) ;Show a decimal representation

_HexShow(0x0000FFFF) ;Pass to function as Hex
_HexShow("0000FFFF") ;Pass to function as string

Func _HexShow($sParam)
    MsgBox(0, "Hex?", $sParam)
EndFunc

what will you say?

[therks]

It's not so much that 0x1 is converted to decimal when it's passed, it's just that it's a different way of specifying a number. Just the same as 1e0 is.

If 1 = 0x1 Then ConsoleWrite(1)
If 1 = 1e0 Then ConsoleWrite(2)
If 0x1 = 1e0 Then ConsoleWrite(3)
If 10 = 0xA Then ConsoleWrite(4)
If 10 = 1e1 Then ConsoleWrite(5)
If 0xA = 1e1 Then ConsoleWrite(6)

No functions to do converting there.

*Edit: But I'm getting off topic here, so I'll stop now.

Edited October 23, 2008 by RobSaunders

[rasim]

RobSaunders

Ok, understand, thanks

[Xand3r]

It's not so much that 0x1 is converted to decimal when it's passed, it's just that it's a different way of specifying a number. Just the same as 1e0 is.

If 1 = 0x1 Then ConsoleWrite(1)
If 1 = 1e0 Then ConsoleWrite(2)
If 0x1 = 1e0 Then ConsoleWrite(3)
If 10 = 0xA Then ConsoleWrite(4)
If 10 = 1e1 Then ConsoleWrite(5)
If 0xA = 1e1 Then ConsoleWrite(6)

No functions to do converting there.

*Edit: But I'm getting off topic here, so I'll stop now.

i think what he meant is :

If 1 = 0x1 Then ConsoleWrite(0x1)
If 1 = 1e0 Then ConsoleWrite(0x2
If 0x1 = 1e0 Then ConsoleWrite(0x3)
If 10 = 0xA Then ConsoleWrite(0x4)
f 10 = 1e1 Then ConsoleWrite(0x5)
If 0xA = 1e1 Then ConsoleWrite(0x6)

Edited October 23, 2008 by TheMadman