How to get the Filepath from a superior Program?

[SpecialK]

Hello,

i want to start the script2.exe from the file script1.exe.

For example:

script1:

Run (C:\Script2.exe)oÝ÷ Ù'+vjëh×6msgbox (1, "Test", "Script1 is located in ????")

I ask myself how i can get the file location from script1 which starts script2. I need the Filepath and the filename for another script which will start a special command which needs the filename.

Thank you in advace

SpecialK

[99ojo]

See help command line parameter.

;-))

Stefan

[dbzfanatic]

Pass it as a parameter.

Script 1:

Run("C:\Script2.exe /" & @ScriptFullPath)

Script 2:

If $cmdline[0] <> "" Then
If $cmdline[1] <> "" Then
MsgBox(1,"Test","Script 1 is located in: " & $cmdline[1])
Endif
Endif

[SpecialK]

There is one problem: I don't have the change to edit script1.

EDIT: I was too quick It works fine without editing the firt program.

Thank you

SpecialK

Edited October 30, 2008 by SpecialK