Initialization of arrays...

[Insolence]

Why in the hell does it keep the 0 after I set this:

$arCharactersTemp[1][0]="A"

returns

A0

Seems like a waste to have to do a StringTrimRight for each one... I tried searching but I had no idea what to look for

[Valik]

You mind giving a fully working example that demonstrates the problem instead of snippets that don't do anything?

[Insolence]

Not at all.

Dim $arCharactersTemp[63][2]

$arCharactersTemp[1][0]="A"
$arCharactersTemp[1][1]="0,-1;-1,0;-1,-1;-7,0;-7,-1;"

Const $arCharacters = $arCharactersTemp

$Test = "0,-1;-1,0;-1,-1;-7,0;-7,-1;"
$String = ""

For $x = 1 to UBound($arCharacters) - 1
   If $arCharacters[$x][1] = $Test Then
      $String = $String & $arCharacters[$x][0]
   EndIf
Next   

MsgBox("","", $String)

Thought it was a simple matter, no idea I had to post a demo.

Edited February 8, 2005 by Insolence

[Valik]

Use == to force a string comparison. By default, an unintialized variable (Or array element) is a number 0 with string representation "". The If statement is performing a numerical comparison between 0 (Unitialized array element's default value) and a string, and since strings are 0 when converted to numbers (In this case), the condition is always true, so you are appending the contents every iteration of the loop.

This isn't an AutoIt bug but rather its normal behavior for the last several months if not since the beginning.

[Insolence]

That's nuts.

Thanks.