Hours difference

[Vladi243]

Hello,

Is there a way in autoit to calculate hours difference?

For example I want to calculate the hours difference between 12:48 and 17:27.

I need the shortest script to calculate this kind of things.

Thanks.

[i542]

_DateDiff UDF.

[Vladi243]

_DateDiff UDF.

Can you give me an example?

I haven't found it in the help file. I only found the function _DateDiff.

[i542]

Can you give me an example?

I haven't found it in the help file. I only found the function _DateDiff.

Thats the one

[Malkey]

Can you give me an example?

I haven't found it in the help file. I only found the function _DateDiff.

You have probably worked this out by now.

_DateDiff() is a little tricky at first use, I found.

Here is an example for the time difference in hours and minutes.

#include <Date.au3>

$sFinishTime = "17:27" ; Proper format in the form of  "2008/02/01 02:15:00"
$sStartTime = "12:48"

; Returns total number of hours only, an integer (no decimal of an hour).
$intTotalHrDiff = _DateDiff('h', "1970/01/01 " & $sStartTime & ":00", "1970/01/01 " & $sFinishTime & ":00")

; Returns total number of minutes only, an integer.
$intTotalMinDiff = _DateDiff('n', "1970/01/01 " & $sStartTime & ":00", "1970/01/01 " & $sFinishTime & ":00")

MsgBox(4096, "", "First Time difference  " & @CRLF & @CRLF & $intTotalHrDiff & " hr " & _
        $intTotalMinDiff - ($intTotalHrDiff * 60) & " min")
        

;=======================================================
; Above shortened
$intTotalHrDiff = _DateDiff('h', "1970/01/01 " & $sStartTime & ":00", "1970/01/01 " & $sFinishTime & ":00")
$sHrMinDiff = $intTotalHrDiff & " hr " & _DateDiff('n', "1970/01/01 " & $sStartTime & ":00", "1970/01/01 " & _
        $sFinishTime & ":00") - ($intTotalHrDiff * 60) & " min"

MsgBox(4096, "", "Second Time difference  " & @CRLF & @CRLF & $sHrMinDiff)

An example for days,hours, and minute difference see

http://www.autoitscript.com/forum/index.ph...st&p=592906