jezzzzy Posted February 18, 2009 Share Posted February 18, 2009 Trying to do a simple string search with this: StringInStr($string,'%;') However this returns 0. If I remove the semicolon it returns a value (just the wrong one). I also tried escaping the semicolon like this: StringInStr($string,'%\;') Still no deal. Can't seem to find out how to search for '%;'. Link to comment Share on other sites More sharing options...
exodius Posted February 18, 2009 Share Posted February 18, 2009 Trying to do a simple string search with this: StringInStr($string,'%;') However this returns 0. If I remove the semicolon it returns a value (just the wrong one). I also tried escaping the semicolon like this: StringInStr($string,'%\;') Still no deal. Can't seem to find out how to search for '%;'. Using the following returns 11 (where it's located in the string) for me, does it not for you? $string = "this is a %; string" MsgBox (0, "", StringInStr($string, "%;")) Link to comment Share on other sites More sharing options...
jezzzzy Posted February 18, 2009 Author Share Posted February 18, 2009 Sure does. Looks like a misdiagnosis on my part. I will post a new topic with the actual problem. Turns out '%;' just wasn't in my string. But it should have been. Sorry for the bad post. Link to comment Share on other sites More sharing options...
exodius Posted February 18, 2009 Share Posted February 18, 2009 Sure does. Looks like a misdiagnosis on my part. I will post a new topic with the actual problem. Turns out '%;' just wasn't in my string. But it should have been. Sorry for the bad post.LOL, it's all good. Link to comment Share on other sites More sharing options...
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