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Champak

Passing the path

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I need to make an app that launches from right clicking the main windows context menu. So basically I right click an file, find my app in the context menu and my app (from the context menu) activates. From what I understand, the file that I right clicked is going to be launched using my app (or something like that). What I want to do is just get the path of the file and not actually open it. How do I do this? Does anyone have any experience?

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#2 ·  Posted (edited)

The file will be in the command argument list, I believe, which is %1 or in $CmdLine[1].

Edit:[\b] You can make a short script or batch to handle it before it gets launched.

Edited by Authenticity

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Thanks.

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