Array Add question

[wimhek]

Can I add the function arrayadd with a 2 dimension array , and if yes, how ?

[Jos]

you can do this by using redim and setting the newly created "sockets" in the array.

This is what _ArrayAdd() does on a single dimension array.

[wimhek]

you can do this by using redim and setting the newly created "sockets" in the array.

This is what _ArrayAdd() does on a single dimension array.

Thakks for your quick answer, but how can I do the redim ? I made this example :

#include <Array.au3>

dim $aaa[1][2]

_ArrayDisplay($aaa)

$aaa [0][0] = "Ape"

$aaa [0][1] = "Nut"

_ArrayDisplay($aaa)

_arrayadd($aaa,"Mary")

_ArrayDisplay($aaa)

[Jos]

You sure you looked in the helpfile?

#include <Array.au3>
dim $aaa[1][2]
_ArrayDisplay($aaa)
$aaa [0][0] = "Ape"
$aaa [0][1] = "Nut"
_ArrayDisplay($aaa)
ReDim $aaa[1][3]
$aaa [0][2] = "Mary"
_ArrayDisplay($aaa)

Jos

[wimhek]

You sure you looked in the helpfile?

Jos

Jos of course I did, but what I want in the end is an arry in this structure

Row Col0 Col1

0 Ape Nut

1 Mary William

[Jos]

something like this should then work for you i guess:

#include <Array.au3>
Dim $aaa[1][2]
_ArrayDisplay($aaa)
_MyAddrayAdd("Ape", "Nut")
_ArrayDisplay($aaa)
_MyAddrayAdd("Mary", "Wim")
_ArrayDisplay($aaa)


Func _MyAddrayAdd($d1, $d2)
    ReDim $aaa[UBound($aaa) + 1][UBound($aaa, 2) + 1]
    $aaa[UBound($aaa) - 1][0] = $d1
    $aaa[UBound($aaa) - 1][1] = $d2
EndFunc  ;==>_MyAddrayAdd

Enjoy,

Jos

[wimhek]

Enjoy,

Jos

Thnx it works, I deleted the +1 in the redim command to avoid adding columns.

#include <Array.au3>

Dim $aaa[1][2]

_ArrayDisplay($aaa)

_MyAddrayAdd("Ape", "Nut")

_ArrayDisplay($aaa)

_MyAddrayAdd("Mary", "Wim")

_ArrayDisplay($aaa)

_MyAddrayAdd("Sister", "Tony")

_ArrayDisplay($aaa)

Func _MyAddrayAdd($d1, $d2)

ReDim $aaa[uBound($aaa) + 1][uBound($aaa, 2) ]

$aaa[uBound($aaa) - 1][0] = $d1

$aaa[uBound($aaa) - 1][1] = $d2

EndFunc ;==>_MyAddrayAdd

[Jos]

You are right .... you see its easy once you get the hang of it.

Jos