How to put a variable in my working RegExp?

[Leonick]

Hey all.

Since the help of the forum(Big thx) i managed to learn the basics of regexp.

But my Problem now is, i wanna replace the word "timer1:" with a variable...tried many things, but not working :-(

#include <Array.au3>

global $hours,$min,$sec

$data = "Timer1:        duration:     1d  03:18:09"
$time = StringRegExp($data, "(?i)timer1:\s*duration:\s*(? :( \d{1,2})d\s*)?(? :( \d{2}) :) ?(? :( \d{2}) :) ?(\d{2})?", 1)




$days = $time[0]
$time = $time[1] & $time[2] & $time[3]

If StringLen($time) = 6 Then
    $Hours = StringLeft($time, 2)
    $min = StringMid($time, 3, 2)
    $sec = StringRight($time, 2)
ElseIf StringLen($time) = 4 Then
    $min = StringLeft($time, 2)
    $sec = StringRight($time, 2)
ElseIf StringLen($time) = 2 Then
    $sec = $time
EndIf


ConsoleWrite("Days:" & $days & @LF)
ConsoleWrite("Hours:" & $Hours & @LF)
ConsoleWrite("Min:" & $min & @LF)
ConsoleWrite("Sec:" & $sec & @LF)

[Authenticity]

String concatenation? or a special feature - AutoIt string content interpolation?

#include <Array.au3>
Opt("ExpandVarStrings", 1)

Global $hours,$min,$sec
Global $sVar = 'Timer1:'

$data1 = "Timer1:        duration:     1d  03:18:09"
$data2 = $sVar & "        duration:     1d  03:18:09"
$data3 = "$sVar$        duration:     1d  03:18:09"

...if I get what you mean.

Edit: By the way, it'd be clever to check if an array's size is matching your expectation before trying to access it's subscripts which may not happen to exists.

Edited July 14, 2009 by Authenticity

[dantay9]

You need to use 3 as a parameter if you want an array as a return value. Use ubound() to check the size of the array.

[Leonick]

And now i dont really get what YOU mean

But i dont wanna punt a variable into my $data, i wanna put the variable into my regexp

I Just wanna replace the word "timer1:" in this line:

$time = StringRegExp($data, "(?i)timer1:\s*duration:\s*(? \d{1,2})d\s*)?(? \d{2}) ?(? \d{2}) ?(\d{2})?", 1)

Edited July 14, 2009 by Leonick

[ResNullius]

And now i dont really get what YOU mean

But i dont wanna punt a variable into my $data, i wanna put the variable into my regexp

I Just wanna replace the word "timer1:" in this line:

$time = StringRegExp($data, "(?i)timer1:\s*duration:\s*(? \d{1,2})d\s*)?(? \d{2}) ?(? \d{2}) ?(\d{2})?", 1)

$var = "timer1"
$time = StringRegExp($data, "(?i)" & $var & ":\s*duration:\s*(? :( \d{1,2})d\s*)?(? :( \d{2}) :) ?(? :( \d{2}) :) ?(\d{2})?", 1)

Beware that if your variable has a space or any other character that has a special meaning in RegExp, then you will have to substitute in the required RegExp equivalent or escape it first.

[Authenticity]

..or to wrap the interpolated string in a \Q...\E block and don't forget (?x) because it seems like a commented pattern.

[ResNullius]

..or to wrap the interpolated string in a \Q...\E block

You know, you learn something new everyday (especially when it comes to RegExp!)

Thanks Authenticity.

[Leonick]

$var = "timer1"
$time = StringRegExp($data, "(?i)" & $var & ":\s*duration:\s*(? :( \d{1,2})d\s*)?(? :( \d{2}) :) ?(? :( \d{2}) :) ?(\d{2})?", 1)

Beware that if your variable has a space or any other character that has a special meaning in RegExp, then you will have to substitute in the required RegExp equivalent or escape it first.

@ResNullius

NOPE doesn't work.

But anyway, i came to the solution by myself, 15mins after i wrote the topic....lol(just forget to answer, since i was too happy to go on scripting)

THIS would be the exact solution:

$time = StringRegExp($data, "(?i)(?:"&$test&")\s*duration:\s*(? :( \d{1,2})d\s*)?(? :( \d{2}) :) ?(? :( \d{2}) :) ?(\d{2})?", 1)

and the /q.../e thing i dont get.....

how would it look like then?

Edited July 14, 2009 by Leonick

[Authenticity]

Either of the two:

; #1
$time = StringRegExp($data, "(?i)(?:\Q"&$test&"\E)\s*duration:\s*(? :( \d{1,2})d\s*)?(? :( \d{2}) :) ?(? :( \d{2}) :) ?(\d{2})?", 1)

; #2
$test = "\QTimer:\E"
$time = StringRegExp($data, "(?i)(?:"&$test&")\s*duration:\s*(? :( \d{1,2})d\s*)?(? :( \d{2}) :) ?(? :( \d{2}) :) ?(\d{2})?", 1)

Edited July 14, 2009 by Authenticity