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erifash

Zipstring encryption routine

3 posts in this topic

A while ago I made a cool program that "zips" a string like a zipper, but never bothered to post it (not to be confused with zipenc). Here's how it works:

1.) take a string

abc

2.) take a randomly generated key

123

3.) encrypt them into their ascii codes

979899 (abc)

495051 (123)

4.) "zip" them together like a zipper

947995809591 (hex encrypted string)

0/0/0/0/0/0/

4 9 5 0 5 1

5.) decrypt them from hex to ascii with chr()

y (i'm not sure if il will display here right)

Yup, so here's the code:

$s = InputBox("zipstring", "string:")

Do
  Do
    $enc = zipstr($s, 1)
    $dec = zipstr($enc, 0)
  Until $dec = $s
  $ok = MsgBox(4, "zipstr", $enc & @CRLF & $dec)
Until $ok = 6

FileWrite("zipstr" & @YEAR & @MON & @MDAY & @HOUR & @MIN & @SEC & ".txt", $enc)

Exit

Func zipstr($str, $ed)
  Local $txt = ""
  If $ed = 1 Then
    $splitcstr = StringSplit(z($str), "")
    $splitckey = StringSplit(z(alpha(StringLen($str))), "")
    For $i = 1 to $splitcstr[0]
      $txt = $txt & $splitcstr[$i] & $splitckey[$i]
    Next
    $txt = a($txt)
    Return $txt
  EndIf
  If $ed = 0 Then
    $csplit = StringSplit(z($str), "")
    For $i = 1 to $csplit[0] - 1 step 2
      $txt = $txt & $csplit[$i]
    Next
    $txt = a($txt)
    Return $txt
  EndIf
  Return 0
EndFunc

Func a($text) ;decrypt
Local $STRG
Local $H
  $STRG = ""
  $H = $text
  For $i = 1 To StringLen($H) Step 2
    $STRG = $STRG & Chr(Dec(StringMid($H, $i, 2)))
  Next
  Return $STRG
EndFunc

Func z($text) ;encrypt
Local $STRG
Local $H
  $H = ""
  $STRG = $text
  For $i = 1 To StringLen($STRG)
    $H = $H & String(Hex(Asc(StringMid($STRG, $i, 1)), 2))
  Next
  Return $H
EndFunc

Func alpha($len)
  $text = ""
  
  Dim $a[86]
  $a[0] = 86

  $r = 1
  For $i = 97 to 122
    $a[$r] = Chr($i)
    $r = $r + 1
  Next

  $r = 1
  For $i = 65 to 90
    $a[$r] = Chr($i)
    $r = $r + 1
  Next

  $r = 1
  For $i = 48 to 57
    $a[$r] = Chr($i)
    $r = $r + 1
  Next

  $a[63] = "-"
  $a[64] = "_"
  $a[65] = "+"
  $a[66] = "="
  $a[67] = "["
  $a[68] = "]"
  $a[69] = "{"
  $a[70] = "}"
  $a[71] = "`"
  $a[72] = "~"
  $a[73] = "'"
  $a[74] = "!"
  $a[75] = "@"
  $a[76] = "#"
  $a[77] = "$"
  $a[78] = "%"
  $a[79] = "^"
  $a[80] = "&"
  $a[81] = "("
  $a[82] = ")"
  $a[83] = ";"
  $a[84] = "."
  $a[85] = ","

  For $i = 1 to $len
    $text = $text & $a[Int(Random(1, $a[0]))]
  Next

  Return $text
EndFunc

What do you think? :)

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Oh, it is very good for just encrypting ONE-WORD strings like passwords and such. The mor spaces you have in the string for some reason the more time it will take to return a valid result. it must have something to do with 32 being 23 backwards...

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Check out the topic "_Basic_ Compression" or something like that it may help you make your program better. Also i think you should make a binary file encrypter lazycat has functions for binary files somewhere i think you could make a fairly good one. :)


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