Sign in to follow this  
Followers 0
madmorgan

getting file name

3 posts in this topic

hello all,

i need help i want to use the file open dialogbox to just get the file name stored in to a varabule example below

#include <ButtonConstants.au3>
#include <EditConstants.au3>
#include <GUIConstantsEx.au3>
#include <WindowsConstants.au3>
#Region ### START Koda GUI section ### Form=
$Form1 = GUICreate("Form1", 306, 151, 192, 124)
$Input1 = GUICtrlCreateInput("Input1", 32, 40, 121, 21)
$Button1 = GUICtrlCreateButton("Button1", 168, 40, 75, 25)
$Button2 = GUICtrlCreateButton("Button2", 88, 88, 75, 25)
GUISetState(@SW_SHOW)
#EndRegion ### END Koda GUI section ###

While 1
    $nMsg = GUIGetMsg()
    Switch $nMsg
        Case $GUI_EVENT_CLOSE
            Exit
        Case $Button1
            $FILENAME = FileOpenDialog("", @UserName, "images (*.JPG)")
                        $PATH = ("")
            MsgBox(0,"",$file)
    EndSwitch
WEnd

i want $FILENAME to have the name of the file eg test.jpg

also from the fileopen box i want the $PATH to hold the path to the file as well.

the only reason i want this like this i want the file name is one var to add to some othere code lator on and the path for somthing else.

if some one can hepl me to do this semmy easy thing then i will be gratefull.

thanks

Share this post


Link to post
Share on other sites



_PathSplit() is useful for this.

#include <ButtonConstants.au3>
#include <EditConstants.au3>
#include <GUIConstantsEx.au3>
#include <WindowsConstants.au3>
#include <File.au3>
#Region ### START Koda GUI section ### Form=
$Form1 = GUICreate("Form1", 306, 151, 192, 124)
$Input1 = GUICtrlCreateInput("Input1", 32, 40, 121, 21)
$Button1 = GUICtrlCreateButton("Button1", 168, 40, 75, 25)
$Button2 = GUICtrlCreateButton("Button2", 88, 88, 75, 25)
GUISetState(@SW_SHOW)
#EndRegion ### END Koda GUI section ###

While 1
    $nMsg = GUIGetMsg()
    Switch $nMsg
        Case $GUI_EVENT_CLOSE
            Exit
        Case $Button1
            $Open = FileOpenDialog("", @UserName, "images (*.JPG)")
            Dim $Drive,$Dir,$Name,$Ext
            _PathSplit($Open,$Drive,$Dir,$Name,$Ext)
            $Name=$Name&$Ext
            $Path=$Drive&$Dir
            MsgBox(0,"",$Name)
            MsgBox(0,"",$Path)
    EndSwitch
WEnd

HKTunes:Softpedia | GoogleCodeLyricToy:Softpedia | GoogleCodeRCTunes:Softpedia | GoogleCodeMichtaToolsProgrammer n. - An ingenious device that turns caffeine into code.

Share this post


Link to post
Share on other sites

#3 ·  Posted (edited)

This should work.

$PATH = FileOpenDialog("", @UserName, "images (*.JPG)")
$temp = StringSplit($PATH, "\")
$FILENAME = $temp[UBound($temp) - 1]
MsgBox(0, "", $FILENAME & @CRLF & $PATH)

Edit: Beat me to it. Didn't know about _pathsplit though, looks useful.

Edited by Hawkwing

The Wheel of Time turns, and Ages come and pass, leaving memories that become legend. Legend fades to myth, and even myth is long forgotten when the Age that gave it birth comes again.

Share this post


Link to post
Share on other sites

Create an account or sign in to comment

You need to be a member in order to leave a comment

Create an account

Sign up for a new account in our community. It's easy!


Register a new account

Sign in

Already have an account? Sign in here.


Sign In Now
Sign in to follow this  
Followers 0