StringRegExp | or operator

[Steveiwonder 0]

Hey all,

I'm a little confused with this one.

The below regexp works fine, it displays in the console

"James Smith

James Brown"

$string = "James Smith James Brown"

$result = StringRegExp($string, "(?i)James\s\w+\b", 3)

if UBound($result) > 0 Then
    for $r in $result
        ConsoleWrite($r & @CRLF)
    Next
EndIf

however if i want to match either James OR Jamie i get some probems, if i change my regexp to:

$result = StringRegExp($string, "(?i)(James|Jamie)\s\w+\b", 3)

I just displays

"James

James"

Should it not Match James or Jamie then continue to look for the Surname with the "\s\w+\b" part of the patern? or am i missing something?

If i then change the string to:

$string = "James Smith Jamie Brown"

I just get:

"James

Jamie"

but no surname.

Apprciate any input.

Thanks.

Steve.

Edited November 23, 2010 by Steveiwonder

[MvGulik 86]

Your running into the problem that your adding a additional next-level capture-group by using '(...)' the way you do.

To correct that you need to drop it back to the same level of the rest of your RE-code. This is done by adding a '?:' directly behind the opening of the group. -> '(?:...)'

So your final RE should be '(?i)(?:james|jamie)\s\w+\b'

See AutoIt 'StringRegExp' help and http://www.regular-expressions.info/ for more RE related information.

Edited November 24, 2010 by MvGulik

[Steveiwonder 0]

.... Thank you works a treat and thanks for the explanation it makes sense

Edited November 24, 2010 by Steveiwonder

[Jimtags 0]

Hello... I would like to ask regarding StringRegExp

My question is.. is't possible to get the count of same letters of two variables?

for example

$var1 = "Jimmy"

$var2 = "Maika"

as you can see $var1 got 3 the same letters to $var2.. and $var2 got 2 the same letters to $var1

i want to get the count of the same letters on each variable ... just like the game FLAMES.

--im waiting for any reply!.. Thanks

[SmOke_N 199]

Hello... I would like to ask regarding StringRegExp

My question is.. is't possible to get the count of same letters of two variables?

for example

$var1 = "Jimmy"

$var2 = "Maika"

as you can see $var1 got 3 the same letters to $var2.. and $var2 got 2 the same letters to $var1

i want to get the count of the same letters on each variable ... just like the game FLAMES.

--im waiting for any reply!.. Thanks

Not without writing the correct pattern!

Anyway:

#include <Array.au3>

Global $svar1 = "Jimmy"
Global $svar2 = "Maika"

Global $icount1 = _MyGetCharCount($svar1, $svar2)
ConsoleWrite("Count: " & $svar1 & " has " & $icount1 & " of the same characters as " & $svar2 & @CRLF)

Global $icount2 = _MyGetCharCount($svar2, $svar1)
ConsoleWrite("Count: " & $svar2 & " has " & $icount2 & " of the same characters as " & $svar1 & @CRLF)


Func _MyGetCharCount($s_var1, $s_var2, $v_case = 0)
    Local $a_split = StringSplit($s_var2, "", 2)
    Local $a_unique = _ArrayUnique($a_split)
    Local $s_pattern = _ArrayToString($a_unique)
    If Not $v_case Then $s_pattern = "(?i)" & $s_pattern
    StringRegExpReplace($s_var1, $s_pattern, "")
    Return @extended
EndFunc

Should obtain what you want

[Jimtags 0]

Owww... It really help...

thanks a lot!

Edited November 24, 2010 by Jimtags

[MvGulik 86]

No completely sure. But,

; (code-tag bug workaround)
    Local $s_pattern = '[' & $s_var2 & ']'

seem equivalent to,

; (code-tag bug workaround)
    Local $a_split = StringSplit($s_var2, "", 3)
    Local $a_unique = _ArrayUnique($a_split)
    Local $s_pattern = _ArrayToString($a_unique)

in its behavior.

(edits: done)

Edited November 24, 2010 by MvGulik

[SmOke_N 199]

No completely sure. But,

; (code-tag bug workaround)
    Local $s_pattern = '[' & $s_var2 & ']'

seem equivalent to,

; (code-tag bug workaround)
    Local $a_split = StringSplit($s_var2, "", 3)
    Local $a_unique = _ArrayUnique($a_split)
    Local $s_pattern = _ArrayToString($a_unique)

in its behavior.

(edits: done)

Mo betta, didn't really take the time to think it out myself ( more time than the op but not enough obviously ).