stringregexp

[golfinhu 1]

people, please help me!

wath's wrong?

$regular = StringRegExp($text, "(\d|[012]\d|3[01])/(\d|1[012])/\d{4}", 3)

i need this return dates on format DD/MM/AAAA

thanks a lot!

[Xenobiologist 47]

#include <Array.au3>
$text = '31/12/2000 and 02-02-1234 and 12/12/2001'
$regular = StringRegExp($text, "([0123]\d)/([01]\d)/(\d{4})", 3)
_ArrayDisplay($regular)

Edited December 23, 2010 by Xenobiologist

[golfinhu 1]

this code is returning the date broken

31

12

2000

12

12

2001

... =[

[Xenobiologist 47]

Oh, I thought that the output should be separated.

Just remove the () and then all should be in one

Mega

[golfinhu 1]

ah I understand, the autoit returns the values separated by groups, $1 $2 $3

I do it is to return the general?

but it worked, thank you

thanks!

Edited December 23, 2010 by golfinhu

[Xenobiologist 47]

ah I understand, the autoit returns the values separated by groups, $1 $2 $3

I do it is to return the general?

but it worked, thank you

thanks!

Sorry, I don't understand whether there is still a question left.

If you do it this way (without the brackets( ) ) then you 'll get the date ich one string like 12/11/2000

#include <Array.au3>
$text = '31/12/2000 and 02-02-1234 and 12/12/2001'
$regular = StringRegExp($text, "[0123]\d/[01]\d/\d{4}", 3)
_ArrayDisplay($regular)

Depends on what you want :-)

Mega

[golfinhu 1]

i've done!

the final code!

$regular = StringRegExp($text, "\b(?:\d|[012]\d|3[01])/(?:0?\d|1[012])/(?:\d{4})", 3)

but his help was very helpful!

thankyou so much!

Edited December 25, 2010 by golfinhu