Exit code help

[superbosu 0]

Hi all!

I have a problem with my script...

How can I set the Exit code of my .exe?

Select

        Case $An = $Bn
            
            Exit (0)


        Case $An < $Bn
            

                     Exit (2)
endselect

I want that if $An = $Bn the .exe file return 0 and if $An < $Bn the .exe return 2

is there a way to do that?

tnx a lot

Edited January 31, 2011 by superbosu

[enaiman 16]

That IS the way to set the exit code.

return code [optional] Integer that sets the script's return code. This code can be used by Windows or the DOS variable %ERRORLEVEL%. The default is 0. Scripts normally set an errorlevel of 0 if the script executed properly; error levels 1 and above typically indicate that the script did not execute properly.

Your script is missing the EndSelect statement; it won't run at all in the current form.

[superbosu 0]

tnx for the reply.. i modified the code.

take a look upper.

mhhh...

is there a way to do the same thing like in DOS ?

DOS command: Exit 2

autoit command: ???

[enaiman 16]

I don't know what is unclear for you?

The code you have is the working one. That is the way it is done.

What is not working for you??