run exe that name changes dynamically

[marshallprank 0]

Hi,

i want to run an exe-file that its name will be changed dynamically. The first Part of the name its XYZ, the second part its V01 (this will be changed dynamically). I want now to write in my code, Run the exe file that begins with XYZ. It is possible?

thanks

[sahsanu 28]

Just an idea... change it to cover your needs.

Note: The search is case insensitive so xyz=XYZ. As soon as there is a match it exits and use that xyz*.exe.

#include <file.au3>
Global $pathtoexe=@ScriptDir & "\", $exetorun, $findingexe
$files=_FileListToArray($pathtoexe,"*.exe")

For $i=1 to $files[0]
    $findingexe=StringRegExp($files[$i],"(?i)^XYZ.*\.exe",1);this regexp is not case sensitive
    If IsArray($findingexe) Then ;the first match will cause to exitloop
        $exetorun=$findingexe[0]
        ExitLoop
    EndIf
Next

If $exetorun = "" Then
    ConsoleWrite("Sorry but I have not found any XYZ*.exe file" & @CRLF)
Else
    ConsoleWrite("The file to be executed is " & $pathtoexe & $exetorun & @CRLF)
EndIf

[marshallprank 0]

thank you its working

[JScript 71]

Hi,

i want to run an exe-file that its name will be changed dynamically. The first Part of the name its XYZ, the second part its V01 (this will be changed dynamically). I want now to write in my code, Run the exe file that begins with XYZ. It is possible?

thanks

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