run exe that name changes dynamically

[marshallprank 0]

Hi,

i want to run an exe-file that its name will be changed dynamically. The first Part of the name its XYZ, the second part its V01 (this will be changed dynamically). I want now to write in my code, Run the exe file that begins with XYZ. It is possible?

thanks

[sahsanu 27]

Just an idea... change it to cover your needs.

Note: The search is case insensitive so xyz=XYZ. As soon as there is a match it exits and use that xyz*.exe.

#include <file.au3>
Global $pathtoexe=@ScriptDir & "\", $exetorun, $findingexe
$files=_FileListToArray($pathtoexe,"*.exe")

For $i=1 to $files[0]
    $findingexe=StringRegExp($files[$i],"(?i)^XYZ.*\.exe",1);this regexp is not case sensitive
    If IsArray($findingexe) Then ;the first match will cause to exitloop
        $exetorun=$findingexe[0]
        ExitLoop
    EndIf
Next

If $exetorun = "" Then
    ConsoleWrite("Sorry but I have not found any XYZ*.exe file" & @CRLF)
Else
    ConsoleWrite("The file to be executed is " & $pathtoexe & $exetorun & @CRLF)
EndIf

[marshallprank 0]

thank you its working

[JScript 66]

Hi,

i want to run an exe-file that its name will be changed dynamically. The first Part of the name its XYZ, the second part its V01 (this will be changed dynamically). I want now to write in my code, Run the exe file that begins with XYZ. It is possible?

thanks

Have you ever wanted to use the invisibility cloak of Harry Potter?