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How to get a next button in custom GUI to go to next screen

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Here is the start of my very first autoit using GUI's. I want to make a series of screens where the user has to input a bit of data, click next, and be presented with a new screen and either new choices or input boxes. I have the first screen the way I want it, but how do I program the next button so it moves to the next window (when I write it), also how do I program exit to do gui_event_close? I'm not new to autoit but I'm fresh on GUI interfaces. Any help is appreciated.

;Version .001

Switches I'm using

Opt("GUIOnEventMode", 1)

#include <GUIConstants.au3>

GUICreate("Employee Lifecycle Process")

GUICtrlCreateCombo ("Please select your name", 10,10)



GUICtrlCreateButton ("Next", 10, 30, 50)

GUICtrlCreateButton ( "Exit", 0, -1)

GUISetState ()

While 1

$msg = GUIGetMsg()

If $msg = $GUI_EVENT_CLOSE Then ExitLoop


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I know in the past most users have suggested creating all your GUI windows( parent and child windows) at the beginning of the script and hide & show the ones that you need.

GUISetOnEvent($GUI_EVENT_CLOSE, '_Terminate')
Func _Terminate()

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Thanks for the help. I used that and a page I found on GUI's on the autoIT web help to figure it out.

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