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Miranda

Binary representation of a number

4 posts in this topic

I did some searching, and some looking at the help files.

I would have expected Binary(12) to output 1100, but I found out there's binary, and then there's binary :unsure:

So I guess after having been enlightened, the question becomes Has anyone made a Binary() function that outputs Numbers in Binary format?

Or is there a function/option/flag I've overlooked somewhere?

Thanks :>

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#2 ·  Posted (edited)

Try this:

#include <String.au3>
MsgBox(0, "Test", Integer2Binary(12))

Func Integer2Binary($in)
    If Not IsInt($in) Then Return SetError(1, 0, "Error")
    If $in = 0 Then Return 0
    Local $bin
    While $in > 0
        $bin &= Mod($in, 2)
        $in = Floor($in / 2)
;~      $in = BitShift($in, 1)
    WEnd
    Return(_StringReverse($bin))
EndFunc

Br,

UEZ

Edited by UEZ

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Another version, linear on size of input (works on large binary data as well, not only on integers:

$n = Binary(Random(0, 123456789, 1))
ConsoleWrite($n & @LF)
ConsoleWrite(_BinaryDump($n) & @LF)

Func _BinaryDump($n)
    $n = Binary($n)
    $n = StringReplace($n, '0', '0000')
    $n = StringReplace($n, '1', '0001')
    $n = StringReplace($n, '2', '0010')
    $n = StringReplace($n, '3', '0011')
    $n = StringReplace($n, '4', '0100')
    $n = StringReplace($n, '5', '0101')
    $n = StringReplace($n, '6', '0110')
    $n = StringReplace($n, '7', '0111')
    $n = StringReplace($n, '8', '1000')
    $n = StringReplace($n, '9', '1001')
    $n = StringReplace($n, 'A', '1010')
    $n = StringReplace($n, 'B', '1011')
    $n = StringReplace($n, 'C', '1100')
    $n = StringReplace($n, 'D', '1101')
    $n = StringReplace($n, 'E', '1110')
    $n = StringReplace($n, 'F', '1111')
    $n = StringReplace($n, '0000x', '0b')
    return($n)
EndFunc

Note: it displays 0b.... to denote binary instead of 0x.... to denote hex, but change it according to your needs.


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Thanks a ton, both of you :unsure:

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