Issue with FindFirstFile loop

[hackersarchangel]

EDIT!!! See code below for solution. I had to Return the variable to outside the function.

Ok so I'm having an issue with AutoIt retaining a variable value from a function. This is the scratchpad code I came up with based on the example in the help file.

If you run the code, it finds the file in the directory specified while in the function. When I exit the function to go into the next part, which is executing the file, the variable is blank.

I did a quick search thinking that all I needed was to make the variable global, but that did not work. So I then declared it Global while in the function and that did not work as well. I'm basically making a tool I can run on multiple machines to help keep them updated, from a server share. I can copy the files down no problem, I'm just looking for a way for it to remember the name of the .exe it pulled and run it with the switches for silent/unattended updates. I have another method, but it's much more complex and bulky in comparison to this because it uses FileInstall to extract the files, then it runs the update tool manually at user request, then runs the updates, and finally it rebuilds itself if updated. Works great if you need an offline option but I'm going for K.I.S.S. with this one.

$program = $Searchdir & "AdbeRdr*.exe"
Func _Search($program)

;Debugging box
MsgBox(48,"Info",$program)

$search = FileFindFirstFile($searchdir & $program)
; Check if the search was successful
If $search = -1 Then
MsgBox(0, "Error", "No files/directories matched the search pattern")
Exit
EndIf
While 1
$file = FileFindNextFile($search)
$run = $file
If @error Then ExitLoop

;Debugging box
MsgBox(4096, "File:", $file)

; !!! The solution !!!
Return ($file)
WEnd
EndFunc

;Checking to make sure the variable remained intact
;This is where it fails because it's not retaining the value needed.
MsgBox(48,"Info","File is: " & $file)

Edited July 3, 2012 by hackersarchangel

[BrewManNH]

Where is the variable $file declared, in what scope?

[DicatoroftheUSA]

Your code does not call the function, and without using byref. If the variable is local in the function, you need to use your function in an expression to store or use the variable. e.g. $a=_MyFunc($stuff)

If the variable is global, then you still need to call the function.

Edited July 3, 2012 by DicatoroftheUSA