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Juggernaut

Quick question

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Juggernaut

Just wondering how can I find out of a certain color pixel is within a certain # of pixels of another color? I'm using the pixel search function and have been researching and trying but to no avail. If someone can point me in the right direction or offer any sort of help that'd be greatly appreciated, thanks! 

Edit: To clarify, this is what i am attempting:

If PIXEL1 is <= 5 pixels FROM PIXEL2
Edited by Juggernaut

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Melba23

Juggernaut,

If you have the location of the 2 pixels then simple maths should give you the answer:

If Abs($iX_1 - $iX_2) <= 5 And Abs($iY_1 - $iY_2) <= 5 Then
    ; Success
Else
    ; Fail
EndIf
Using the absolute difference is a pretty standard method for determining the "nearness" of linear values. :)

M23


Any of my own code posted anywhere on the forum is available for use by others without any restriction of any kind._______My UDFs:

Spoiler

ArrayMultiColSort ---- Sort arrays on multiple columns
ChooseFileFolder ---- Single and multiple selections from specified path treeview listing
Date_Time_Convert -- Easily convert date/time formats, including the language used
ExtMsgBox --------- A highly customisable replacement for MsgBox
GUIExtender -------- Extend and retract multiple sections within a GUI
GUIFrame ---------- Subdivide GUIs into many adjustable frames
GUIListViewEx ------- Insert, delete, move, drag, sort, edit and colour ListView items
GUITreeViewEx ------ Check/clear parent and child checkboxes in a TreeView
Marquee ----------- Scrolling tickertape GUIs
NoFocusLines ------- Remove the dotted focus lines from buttons, sliders, radios and checkboxes
Notify ------------- Small notifications on the edge of the display
Scrollbars ----------Automatically sized scrollbars with a single command
StringSize ---------- Automatically size controls to fit text
Toast -------------- Small GUIs which pop out of the notification area

 

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jchd

OTOH if you want to determine whether a pixel lies in the disk whose radius is your threshold (euclidean distance), you'll have to test otherwise:

Local $x1 = 23, $y1 = 487
Local $x2 = 24, $y2 = 490
Local $x3 = 21, $y3 = 484

ConsoleWrite("Distance between pixel 1 and pixel 2 = " & _Dist($x1, $y1, $x2, $y2) & @LF)
ConsoleWrite("Distance between pixel 1 and pixel 3 = " & _Dist($x1, $y1, $x3, $y3) & @LF)
ConsoleWrite("Distance between pixel 2 and pixel 3 = " & _Dist($x2, $y2, $x3, $y3) & @LF)

Func _Dist($x1, $y1, $x2, $y2)
    Return Sqrt(($x1 - $x2) ^ 2 + ($y1 - $y2) ^ 2)
EndFunc

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