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Start script with file path

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I want to start a script with this:

ShellExecute(Test.exe C:ExampleTest.txt)

and have it save C:ExampleTest.txt to a variable

if started with just Test.exe then

$sFile = FileOpenDialog('Select File', @DesktopDir, 'Text File (*.txt)', 1)

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I figured it out:

ShellExecute(@ScriptDir & "\Test.exe", "Test.txt")

If $CmdLineRaw <> "" Then
    Local $sFile = $CmdLineRaw
    Local $sFile = FileOpenDialog('Select File', @DesktopDir, 'Text File (*.txt)', 1)

of course shellexecute will be in another script opening up test.exe

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