VenusProject2 2 Posted December 23, 2014 (edited) Hi All I'm new to this, I have the following code it does POST the data 'silently' however, I'm wondering what I need to also have the code open the URL in a browser window & POST the data? Any help really appreciated, thanks $sPD2 = 'email=' & $sEmail & '&pc_guid=' & $sUniqueID $oHTTP2 = ObjCreate("winhttp.winhttprequest.5.1") $oHTTP2.Open("POST", "https://MyURL/MyPhpScript.php", False) $oHTTP2.SetRequestHeader("Content-Type", "application/x-www-form-urlencoded") ; Performing the Request $oHTTP2.Send($sPD2) ; Download the body response if any, and get the server status response code. $oReceived2 = $oHTTP2.ResponseText $oStatusCode2 = $oHTTP2.Status ;MsgBox(0,"",$oStatusCode & " " & $oReceived) If $oStatusCode2 <> 200 Then MsgBox(4096, "Internet", "Experienced problem with internet", 3);tempmsg Else MsgBox(0,"","Sent POST data = " & $sPD2) EndIf Edited December 23, 2014 by VenusProject2 Share this post Link to post Share on other sites
