Luigi Posted February 10, 2015 Share Posted February 10, 2015 (edited) Greetings forum! You know another way to do set a new value in nested Scripting.Dictionary? I make this litle function called 'set', you pass the Scripting.Dictionary, the path and the value... The function split the path, and set the new value. I found this way, there are another? Br, Detefon expandcollapse popup#include <Array.au3> Local $SD = "Scripting.Dictionary" Local $oo = ObjCreate($SD) $oo.Add("key", 0) $oo.Add("array", ObjCreate($SD)) $oo.Item("array").Add("one", 1) $oo.Item("array").Add("two", 2) ConsoleWrite("before" & @LF) ConsoleWrite(" key[ " & $oo.Item("key") & " ]" & @LF) ConsoleWrite("array.one[ " & $oo.Item("array").Item("one") & " ]" & @LF) set($oo, "key", 1) set($oo, "array.one", 6) Func set(ByRef $oo, $path, $value) Local $oTemp = $oo Local $aPath = StringSplit($path, ".") Local $sPath = '.Item("' & _ArrayToString($aPath, '").Item("', 1) & '")' Switch $aPath[0] Case 1 With $oo .Item($aPath[1]) = $value EndWith Case 2 With $oo .Item($aPath[1]).Item($aPath[2]) = $value EndWith Case 3 With $oo .Item($aPath[1]).Item($aPath[2]).Item($aPath[3]) = $value EndWith EndSwitch EndFunc ;==>set ConsoleWrite(@LF & "after" & @LF) ConsoleWrite(" key[ " & $oo.Item("key") & " ]" & @LF) ConsoleWrite("array.one[ " & $oo.Item("array").Item("one") & " ]" & @LF) Edited February 10, 2015 by Detefon Visit my repository Link to comment Share on other sites More sharing options...
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