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NiceBoy1234

Get Array Index of for loop in if statement

13 posts in this topic

How can I access a variable with its index of a loop inside my if statment.

Code:
 

For $i = 0 To UBound($aFileListFootageFolderRe_01) - 1
      ...
      Next

     If $getTimeNewFootageFolderInit_01 <> $getTimeNewFootageFolder_01 And $aFileListFootageFolderRe_01[$i] == 11) Then
      ...
     EndIf

I get following error while doing this:
 

Array variable has incorrect number of subscripts or subscript dimension range exceeded.:

Thus the error points at this

$aFileListFootageFolderRe_01[$i]

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to debug, before the "For" section, call _ArrayDisplay() to make sure the array exists and is 1-D.

also, i assume you mean the "Next" line should be after the If...EndIf, so it is inside the loop and performed over every element, right? if not, then make sure $i has a valid value after the loop is done.

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#3 ·  Posted (edited)

No Next should not be after If Endif, so after the for loop I have to declare my "i" like $i = 0.
Thus what do you mean excatly with 1-D?
nevermind 1 Dimensional :)

Edited by NiceBoy1234

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Ok I did _ArrayDisplay() and it's 1 Dimensional.

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I gave $i a valid value after the looop but did not solve it either

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#6 ·  Posted (edited)

You could use _ArraySearch to get the index of the value you're looking for

#include <Array.au3>
Global const $aValues[] = ["This", "Is", "a", "test", "AutoIt", "Rulez!"]
Global const $sValueToFind1 = "AutoIt"
Global const $sValueToFind2 = "Cake"
Global const $iIndex1 = _ArraySearch($aValues, $sValueToFind1)
Global const $iIndex2 = _ArraySearch($aValues, $sValueToFind2)

If ($iIndex1 > -1) Then
    MsgBox("", "", "Found '" & $aValues[$iIndex1] & "' at index " & $iIndex1)
Else
    MsgBox("", "", "Could not find the value '" & $sValueToFind1 & "' for index $iIndex1")
EndIf

If ($iIndex2 > -1) Then
    MsgBox("", "", "Found '" & $aValues[$iIndex2] & "' at index " & $iIndex2)
Else
    MsgBox("", "", "Could not find the value '" & $sValueToFind2 & "' for index $iIndex2")
EndIf

 

Edited by InunoTaishou

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please attach a screenshot of _ArrayDisplay (or a console output you can generate with this) and the value of $i right before the offending "If".

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_ArrayDisplay showed a window with this:

[0] = "xxx"

[1] = "xxx"

[2] = "xxx"

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and $i ...?

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$i stands for [0][1][2] or not?,
it jsut showed

[0] = "xxx"

[1] = "xxx"

[2] = "xxx"

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add this line before the offending "If" line:

ConsoleWrite('$i = ' & $i & @CRLF)

$i should be an integer. 0, 1 or 2 are valid values in this case.

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yep I get 0, 1, 2

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