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Trying to get x and y pos of windows without borders


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Hi, I'm trying to get x and y pos of browser(firefox) but without borders and window title.
I tried ControlGetPos but it doesn't work. _FFGetPostion from FF.au3 also doesn't work. I was thinking: hey can I disable the window title and border? and I found answer: yes
So I copy some function of anygui.au3 and I got this:
 

$Style = 0x00C00000
$ExStyle = -1
$result = _TargetStyle("unset", 1, $Style, $ExStyle, $handle)

I like it but in windows 10 there is a little white bar on top, like 5px.
I tested this on old computer with classic theme windows and it works fine.
I know that I can count these pixels and it works but only on my computer.
I want universal script that always work.

So my question is: Can I change window theme to classic but only one which I want?
Or if you know how can I get this pos in another way please let me know.

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33 minutes ago, Daavis said:

Hi, I'm trying to get x and y pos of browser(firefox) but without borders and window title.
I tried ControlGetPos but it doesn't work. _FFGetPostion from FF.au3 also doesn't work.

Didn't work is no error description which helps solving the issues you had. So, please make runable reproduser scripts showing your issues.

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#include <FF.au3>
#include <Array.au3>

_FFStart("https://www.google.com")
$Handle = _FFWindowGetHandle()
WinMove($Handle, "", 0, 0)
$Pos = _FFGetPosition()
_ArrayDisplay($Pos)

This code return me this:
Row|Col 0
[0]|-1
[1]|-1
[2]|-8
[3]|-31
[4]|700
[5]|650

As you can see I moved window to 0, 0 so this return position is wrong
[1] should be greater then 0 not -8
FF.au3 using ControlGetPos for this function so something goes wrong.

Local $aContent = ControlGetPos(_FFCmd(".title"), "", _FFWindowGetHandle())

 

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