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    • By Zaoka
      Hi guys
      Need little help with filtering.
      I'm trying to filter specific weeks from power pivot table using this code recorded with Excel VBA :
       
      #include <Excel.au3> Global $oExcel = _Excel_Open() Global $oWorkbook = _Excel_BookOpen($oExcel, "C:\Users\....\Orders.xlsb") $oWorkbook.PivotTables("PivotTable1").PivotFields( _ "[Report 2].[Week].[Week]").VisibleItemsList = Array( _ "[Report 2].[Week].&[10]", "[Report 2].[Week].&[11]", _ "[Report 2].[Week].&[12]", "[Report 2].[Week].&[13]", _ "[Report 2].[Week].&[14]", "[Report 2].[Week].&[15]") But get error
      error: Array(): undefined function. Not sure how to resolve this.
    • By LxP
      I'm trying to pass a nested array to a function, such that the function alters the inner array.
      I was surprised to find that this minimal reproducible example, despite its use of ByRef, seems to pass a copy of the inner array to the function:
      #include <Array.au3> ; a boring old array Local $aInnerArray[5] = [1, 2, 3, 4, 5] ; a one-element array containing a reference to the other array Local $aOuterArray[1] = [$aInnerArray] ; intention: take a nested array and alter its inner array ; reality: the inner array seems to be getting copied Func ChangeIt(ByRef $aOuter) Local $aInner = $aOuter[0] $aInner[2] = 0 EndFunc ; Expected: [1, 2, 3, 4, 5] ; Actual: [1, 2, 3, 4, 5] ✔ _ArrayDisplay($aInnerArray, 'Before') ; $aOuterArray passed by-ref, should receive reference to $aInnerArray ; Therefore should change $aInnerArray to [1, 2, 0, 4, 5] ChangeIt($aOuterArray) ; Expected: [1, 2, 0, 4, 5] ; Actual: [1, 2, 3, 4, 5] ✘ _ArrayDisplay($aInnerArray, 'After') I suspect that either:
      the copy is taking place in the first line of the function (I couldn't find a way to access the inner array without first assigning it to a variable though); or ByRef doesn't propagate into inner levels of the data structure being passed, which seems less likely to me. Could someone please point me in the right direction to get this working as intended?
      Update: the answer
      ; WRONG: ; a one-element array containing a reference to the other array Local $aOuterArray[1] = [$aInnerArray] The assumption I made about this code is wrong—it actually copies $aInnerArray into $aOuterArray, so there are now two unrelated $aInnerArray instances.  It is not possible to store arrays in other arrays by reference.
      If it is necessary to refer to a mutable array in multiple places, consider holding it in a global variable.  Where a collection of mutable arrays needs to be accessed in multiple places (as in my case), consider storing them in a global array and referring to each sub-array by index (also known as the Registry pattern).
    • By VinMe
      HELLO All,
      is there any function in Auto it to Remove the repeating  strings separated by ","  which is present in the array.
      ex.
      Available state
      a[0]= D97,D96,,D85,D86,D85,D86,D85,D86,D85,,D86,D85,D86,D85,D86
      a[1]=D85,D24,,,,,D85
      Required state
      a[0]= D97,D96,D85,D86,
      a[1]=D85,D24
      thank  you in advance!
      vin!
    • By Luigi
      Greetings,
       
      Someone can help-me to translate this Python's code to AutoIt?
       
      Python (source: https://repl.it/repls/InstructiveDarkslategreyJackrabbit)
      str = 'age=12,name=bob,hobbies="games,reading",phrase="I\'m cool!"' key = "" val = "" dict = {} parse_string = False parse_key = True # parse_val = False for c in str: print(c) if c == '"' and not parse_string: parse_string = True continue elif c == '"' and parse_string: parse_string = False continue if parse_string: val += c continue if c == ',': # terminate entry dict[key] = val #add to dict key = "" val = "" parse_key = True continue elif c == '=' and parse_key: parse_key = False elif parse_key: key += c else: val+=c dict[key] = val print(dict.items()) Python's output:
      [('phrase', "I'm cool!"), ('age', '12'), ('name', 'bob'), ('hobbies', 'games,reading')] AutoIt
      #include-once #include <Array.au3> #include <StringConstants.au3> Global $opt $opt = "estado = """" , cep = """", idade=32, nome = ""Luismar"", campo=""campo = campo""" $opt = "age=12,name=bob,hobbies=""games,reading"",phrase=""I\'m cool!""" ConsoleWrite($opt & @LF) Local $arr = StringSplit($opt, "", $STR_CHRSPLIT) Local $key = "" Local $val = "" Local $dict = ObjCreate("Scripting.Dictionary") Local $parse_string = False Local $parse_key = True Local $c For $ii = 1 To $arr[0] $c = $arr[$ii] If $c == '"' And Not $parse_string Then $parse_string = True ContinueLoop ElseIf $c == """" And $parse_string Then $parse_string = False ContinueLoop EndIf If $parse_string Then $val &= $c ContinueLoop EndIf If $c = "," Then $dict.Add($key, $val) $key = "" $val = "" $parse_key = True ContinueLoop ElseIf $c == "=" And $parse_key Then $parse_key = False ElseIf $parse_key Then $key &= $c Else $val &= $c EndIf Next $dict.Add($key, $val) ; missing this line... For $each In $dict ConsoleWrite($each & " = " & $dict.Item($each) & @LF) Next AutoIt's output
      age=12,name=bob,hobbies="games,reading",phrase="I\'m cool!" age = 12 name = bob hobbies = games,reading  
      Best regards.
       
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