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Please Help a newbie! (Variables and ShellExecute)


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Hello everyone,

I'm new on Autoit and I'm trying to run two variables, one with parameters.

 

Local $go2 = @AppDataDir & "\test\file2.exe"
Local $go1 = @AppDataDir & "\teste\file1.exe"


if fileexists($go2) then

ShellExecute ('"$go1" /parameters1 /parameters2', ($go2))

Exit

else
msgbox(0, "My Test", "File not found" & @LF & "My url")
endif

This should run like this (exemple):

"path1/file1.exe /parameters1 /parameters2" "path2/file2.exe"

But, dont work. Please, help-me.

 

thanks!

 

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@soh Your variable should not be inside quotes in your ShellExecute statement. It would just be ShellExecute($go1, ......

 

 

Edited by JLogan3o13

"Profanity is the last vestige of the feeble mind. For the man who cannot express himself forcibly through intellect must do so through shock and awe" - Spencer W. Kimball

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You would enter the parameters in quotes, but not the variable. Like so:

ShellExecute ($go1,  '/parameters1 /parameters2', $go2)

 

Edited by JLogan3o13

"Profanity is the last vestige of the feeble mind. For the man who cannot express himself forcibly through intellect must do so through shock and awe" - Spencer W. Kimball

How to get your question answered on this forum!

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This works:

Local $go2 = @AppDataDir & "\test\file2.exe"
Local $go1 = @AppDataDir & "\teste\file1.exe"


If FileExists($go2) Then

    ShellExecute($go1, "/parameters1 /parameters2")
    ShellExecute($go2)

    Exit

Else
    MsgBox(0, "My Test", "File not found" & @LF & "My url")
EndIf

Not sure why you would put a  executable variable as a parameter for 'workingdir' but if you you want both executables to run then this should do it.

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Try this:

Run(@AppDataDir & "\test\file1.exe /op /sc /nt " & @AppDataDir & "\test\file2.exe")

 

"Profanity is the last vestige of the feeble mind. For the man who cannot express himself forcibly through intellect must do so through shock and awe" - Spencer W. Kimball

How to get your question answered on this forum!

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