set multiple path at environment variables in windows and run it using autoit

[lattey]

i have one application that need to run under below condition:

1. the application start in at path : C:\NETSL\system\Config

2. the target path is C:\NETSL\system\netsl.exe

if i run the application using only C:\NETSL\system\netsl.exe , the application run differently. 

so, i thinking to set the path at environment variable but nothing happened. 
what i do is i set the variable at control panel - > System -> advanced system settings -> environment variables 
    
 

  variable  name = TEST_PATH
    variable value = C:\NETSL\system\Config;C:\NETSL\system\netsl.exe

and run using autoit:

   

Local $sEnvVar = EnvGet("TEST_PATH")
MsgBox("","", $sEnvVar )
ShellExecuteWait($sEnvVar)

am i doing it wrongly?

i also need to run another application as below:

1. C:\NETSL\system\initnetsl.exe "C:\NETSL\system\Config\Users.xxx"

but i dont know how to called the exe. any idea?

Edited May 22, 2017 by lattey

[Floops]

Have you tried it like this?

 

ShellExecute("C:\NETSL\system\netsl.exe", "C:\NETSL\system\Config")
ShellExecute("C:\NETSL\system\initnetsl.exe", "C:\NETSL\system\Config\Users.xxx")

 

[lattey]

yes, i already tried that, it show error for both.

[Subz]

Wouldn't the third parameter be the working directory for ShellExecute?

ShellExecute("C:\NETSL\system\initnetsl.exe", "C:\NETSL\system\Config\Users.xxx", "C:\NETSL\system\Config")
Or
Run("C:\NETSL\system\initnetsl.exe C:\NETSL\system\Config\Users.xxx", "C:\NETSL\system\Config")

[lattey]

thanks guys. im using the solution from 

subz and it works perfectly.