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Re-assigning values to an array - (Moved)


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I am missing something here...I do not know why the second to last array assignment of this code snippet does not work

Sorry if I am not using the correct "buzz" words to explain what I am intuitively expecting to be OK is not OK.

Works of course-->: two arrays, same dimensions, different values, "A=B" works after the two arrays are declared and populated with Local statement .

But "A=hard coded array" does not work even though "hard coded" array has same dimensions  as the declared array and is the same as was assigned to  array B in its declaration statement.

As expected from searches, re-declaring the "A" array works to re-assign new array values, but it seems strange to me to have to redeclare an array when I just want to re-assign the values and not change its dimensions.

Obviously not  a burden to use "Local" again, but I do not see why this is needed.

Worded differently....

 

IF

Local ArrayA=an array of values

Local ArrayB=an array of values

 

Then

Array A = B works if dimensions are the same.

But A=[array of values of B in its declaration]  does not work.

I suspect, which is not clear in the help file for the arrays that I found, not only do you have to use Local/GLobal/Dim when you first declare an array, you must also use it whenever you want to re-assign values to an array other than with a variable (A=B).

Of course you can also loop through the array using cell indices for all its cells, but this, to me is also cumbersome.

 

 

#include <Array.au3>

Local $aArray1D_Col[1][10] = [["AA", "BB", "CC",44,55,66,77,88,99,"JJ"]]
_ArrayDisplay($aArray1D_Col)

Local $aSecondArray1D_Col[1][10]=[["11", "22", "33",44,55,66,77,88,99,"TenthCOL"]]
_ArrayDisplay( $aSecondArray1D_Col)

$aArray1D_Col=$aSecondArray1D_Col  ;works
_ArrayDisplay($aArray1D_Col)

;Why does this assignment of values to the array not work?
$aArray1D_Col=[["11", "22", "33",44,55,66,77,88,99,"JJ"]]

;But does if you re-initialize the array with LOCAL
Local $aArray1D_Col[1][10]=[["11", "22", "33",44,55,66,77,88,99,"NEW TenthCOL"]]
_ArrayDisplay($aArray1D_Col)

 

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In AutoIt, array literals are only supported inside a declaration or redeclaration. For instance you can't write If $a = [1, 2, 3] Then ...

Use Dim to redeclare a variable: this preserve its scope (local/global).

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  • Moderators

Moved to the appropriate forum.

Moderation Team

Public_Domain.png.2d871819fcb9957cf44f4514551a2935.png Any of my own code posted anywhere on the forum is available for use by others without any restriction of any kind

Open spoiler to see my UDFs:

Spoiler

ArrayMultiColSort ---- Sort arrays on multiple columns
ChooseFileFolder ---- Single and multiple selections from specified path treeview listing
Date_Time_Convert -- Easily convert date/time formats, including the language used
ExtMsgBox --------- A highly customisable replacement for MsgBox
GUIExtender -------- Extend and retract multiple sections within a GUI
GUIFrame ---------- Subdivide GUIs into many adjustable frames
GUIListViewEx ------- Insert, delete, move, drag, sort, edit and colour ListView items
GUITreeViewEx ------ Check/clear parent and child checkboxes in a TreeView
Marquee ----------- Scrolling tickertape GUIs
NoFocusLines ------- Remove the dotted focus lines from buttons, sliders, radios and checkboxes
Notify ------------- Small notifications on the edge of the display
Scrollbars ----------Automatically sized scrollbars with a single command
StringSize ---------- Automatically size controls to fit text
Toast -------------- Small GUIs which pop out of the notification area

 

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7 hours ago, jchd said:

In AutoIt, array literals are only supported inside a declaration or redeclaration. For instance you can't write If $a = [1, 2, 3] Then ...

Use Dim to redeclare a variable: this preserve its scope (local/global).

THANKS!  Especially the "hint" on using Dim for future assignments to literals so it preserves the original declared scope, not particularly obvious from the help files.

 

Sorry about posting in wrong forum, I will try to do better.

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