Jump to content

Recommended Posts

May not be useful for others but I do it this way when needed to delete lots of column.

#include <Array.au3>
#include "ArrayDeleteCol.au3"

Local $x_Array[][] = [[0,1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19,20,21,22,23,24,25,26,27,28,29,30,31,32,33,34,35]]
Local $x_ColumnToDelete = '1;28;6-9;13;13;15;18-24;4;30'

__Array_DeleteColumn($x_Array, $x_ColumnToDelete)

@pixelsearch version




Edited by jugador
Link to post
Share on other sites
  • Moderators

Just out of curiosity, how does this differ - or what advantages are there - over the included _ArrayColDelete function?

"Profanity is the last vestige of the feeble mind. For the man who cannot express himself forcibly through intellect must do so through shock and awe" - Spencer W. Kimball

How to get your question answered on this forum!

Link to post
Share on other sites


Have you tried the code? I guess not ;)

Can we pass list of column (like  $x_ColumnToDelete in 1st post) want to delete in _ArrayColDelete.
If yes I don’t know that, my mistake.

Sometime I need to delete multiple columns many a times. It’s useful for such purpose for :whistle:  me.

Link to post
Share on other sites

Hi @jugador, interesting topic indeed.

May I suggest another approach to avoid several calls to _ArrayColDelete (17 in your example + 17 Redim etc...) . In fact there is no call to _ArrayColDelete in the code below. There's probably a couple of error checking to add but you'll get the idea and It should go faster (the more columns to delete, the faster it should be). Please indicate if something goes wrong with this approach.


; Replace this :

;~  ;~ Sort a 1D Array
;~  _ArraySort($o_Column, 1)

;~  ;~ Delete Column
;~  For $i = 0 To UBound($o_Column) - 1
;~      _ArrayColDelete($0_Array, $o_Column[$i])
;~  Next

; With that :

    ; Sort a 1D Array of columns to delete (ascending, for $jStart and binary search to come)
    Local $jStart = $o_Column[0] ; 1st column to delete, i.e. don't touch column(s) on its left
    ConsoleWrite("$jStart = " & $jStart & @crlf) ; 1 in jugador's example
    _ArrayDisplay($o_Column, "To delete, asc") ; 17 cols

    ; Create a 1D array of columns to keep (ascending)
    Local $aColsToKeep[Ubound($0_Array, 2) - Ubound($o_Column)] ; 36 - 17 = 19 cols to keep
    ConsoleWrite("Ubound($aColsToKeep) = " & Ubound($aColsToKeep) & @crlf) ; 19 cols
    Local $iIndex = - 1
    For $i = 0 To Ubound($0_Array, 2) - 1
        If _ArrayBinarySearch($o_Column, $i) = -1 Then ; not found (-1)
            $iIndex += 1 ; 0+
            $aColsToKeep[$iIndex] = $i
    _ArrayDisplay($aColsToKeep, "To keep, asc") ; 19 cols

    ; Position each element at its place, then 1 final Redim to delete rightmost column(s)
    For $i = 0 To Ubound($0_Array) - 1
        For $j = $jStart To Ubound($aColsToKeep) - 1
            $0_Array[$i][$j] = $0_Array[$i][$aColsToKeep[$j]]
    ReDim $0_Array[Ubound($0_Array)][Ubound($aColsToKeep)] ; 19 cols



Link to post
Share on other sites
  • 4 weeks later...

__Array_DeleteColumn (Version 3) ==>  speed improve :).
not deleting the modified version of @pixelsearch for speed comparison.

comparison with_ArrayColDelete

#include <Array.au3>
#include "ArrayDeleteCol.au3"

Local $x1_Array[][] = [[0,1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19,20,21,22,23,24,25,26,27,28,29,30,31,32,33,34,35]]
Local $x_ColumnToDelete = '1;28;6-9;13;13;15;18-24;4;30'

Local $1_Timer = TimerInit()
__Array_DeleteColumn($x1_Array, $x_ColumnToDelete)
ConsoleWrite('Version 3: ' & TimerDiff($1_Timer) & @CRLF)

Local $x3_Array[][] = [[0,1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19,20,21,22,23,24,25,26,27,28,29,30,31,32,33,34,35]]
Local $To_Delete[] = [30,28,24,23,22,21,20,19,18,15,13,9,8,7,6,4,1]

Local $3_Timer = TimerInit()
For $i = 0 To UBound($To_Delete) - 1
    _ArrayColDelete($x3_Array, $To_Delete[$i])
ConsoleWrite('Original: ' & TimerDiff($3_Timer) & @CRLF)



Version 3: 0.420298933679558
Original: 0.735610623309268


Edited by jugador
Link to post
Share on other sites

Create an account or sign in to comment

You need to be a member in order to leave a comment

Create an account

Sign up for a new account in our community. It's easy!

Register a new account

Sign in

Already have an account? Sign in here.

Sign In Now
  • Recently Browsing   0 members

    No registered users viewing this page.

  • Create New...