HotKeySet() and 'Variable used without being declared.'

[ibecko]

hi, how I can globaly fix non declared variable issue when I run function from HotKeySet() ?

HotKeySet('{ESC}', 'function_test')

function_test()
function_test('blablabla')

Func function_test($var='')
   If     IsDeclared('var') then ConsoleWrite("when this function run like function_test() or function_test('var test') from code work fine, $var is declared, $var='"&$var&"', now press ESC"&@CRLF&@CRLF)
   If Not IsDeclared('var') then ConsoleWrite("when this function run pressing key from HotKeySet() $var not declred and script exit with error 'Variable used without being declared.'"&@CRLF&@CRLF)
   If Not IsDeclared('var') then ConsoleWrite("$var='"&$var&"'"&@CRLF&@CRLF)
EndFunc

While True
   Sleep(20)
WEnd

 

I know, its possible to add firt line on function where I check if variable is declared and if no declare it but why? I declare variable on function parameter and it works for scripts but no for HotKeySet

 

thanks

[Danp2]

From the help file --

Quote

The called function can not be given parameters. They will be ignored.

You could use a 2nd function in the HotKeySet that calls the original function.

[ibecko]

no, I dont wanna call any function parameter from hotkeyset, try my code and press ESC

my question is: Func function_test($var='') has local declared  $var variable (only for this function) and why hotkeyset ignore this declaration

 

I must check declaration and redeclare $var again, then works fine, but this is duplicate declaration of local variable

HotKeySet('{ESC}', 'function_test')

function_test()
function_test('blablabla')

Func function_test($var='')
   If Not IsDeclared('var') then $var=''
   If     IsDeclared('var') then ConsoleWrite("when this function run like function_test() or function_test('var test') from code work fine, $var is declared, $var='"&$var&"', now press ESC"&@CRLF&@CRLF)
   If Not IsDeclared('var') then ConsoleWrite("when this function run pressing key from HotKeySet() $var not declred and script exit with error 'Variable used without being declared.'"&@CRLF&@CRLF)
   If Not IsDeclared('var') then ConsoleWrite("$var='"&$var&"'"&@CRLF&@CRLF)
EndFunc

While True
   Sleep(20)
WEnd

 

[ioa747]

25 minutes ago, Danp2 said:

You could use a 2nd function in the HotKeySet that calls the original function.

try this way

HotKeySet('{ESC}', 'function_ESC')

function_test()
function_test('blablabla')

Func function_test($var='')
   If Not IsDeclared('var') then $var=''
   If     IsDeclared('var') then ConsoleWrite("when this function run like function_test() or function_test('var test') from code work fine, $var is declared, $var='"&$var&"', now press ESC"&@CRLF&@CRLF)
   If Not IsDeclared('var') then ConsoleWrite("when this function run pressing key from HotKeySet() $var not declred and script exit with error 'Variable used without being declared.'"&@CRLF&@CRLF)
   If Not IsDeclared('var') then ConsoleWrite("$var='"&$var&"'"&@CRLF&@CRLF)
EndFunc

Func function_ESC()
    function_test('blablabla')
EndFunc


While True
   Sleep(20)
WEnd

 

[ibecko]

ok, now I understand, hotkeyset can't read variable declared as parameter... best way is checking and declaring all variables, thanks

[ioa747]

https://www.autoitscript.com/autoit3/docs/functions/HotKeySet.htm

The called function ( from HotKeySet ) can not be given parameters. They will be ignored.

that's why  You should use a 2nd function in the HotKeySet that calls the original function.

Edited February 2, 2023 by ioa747