litlmike Posted March 2, 2006 Share Posted March 2, 2006 (edited) I am thinking there is a better way to do this. Any suggestions? Trying to calculate the Friday of that current week. I want $date3 to always equal the YYYY/MM/DD of the current week. #include <Date.au3> $date1 = _DateToDayOfWeek (@YEAR, @MON, @MDAY) $date2 = 6 - $date1 $date3 = _DateAdd ( "d", $date2, _NowCalcDate()) MsgBox( 4096, "", $date3) Edited March 3, 2006 by litlmike _ArrayPermute()_ArrayUnique()Excel.au3 UDF Link to comment Share on other sites More sharing options...
SpookMeister Posted March 2, 2006 Share Posted March 2, 2006 (edited) @WDAY gives you a numeric for the current day of the week (1-7=Sun-Sat) so... $days = 6 - @WDAY ; 6 being the number representing Friday if $days < 0 Then $days = $days + 7 msgbox(0,"",$days & " days till Friday") Edited March 2, 2006 by SpookMeister [u]Helpful tips:[/u]If you want better answers to your questions, take the time to reproduce your issue in a small "stand alone" example script whenever possible. Also, make sure you tell us 1) what you tried, 2) what you expected to happen, and 3) what happened instead.[u]Useful links:[/u]BrettF's update to LxP's "How to AutoIt" pdfValuater's Autoit 1-2-3 Download page for the latest versions of Autoit and SciTE[quote]<glyph> For example - if you came in here asking "how do I use a jackhammer" we might ask "why do you need to use a jackhammer"<glyph> If the answer to the latter question is "to knock my grandmother's head off to let out the evil spirits that gave her cancer", then maybe the problem is actually unrelated to jackhammers[/quote] Link to comment Share on other sites More sharing options...
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