# Is This Correct?

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Havent tested yet but im shur it wont work

I need it to make \$8 to add like so each one \$8_1,\$8_2,\$8_3

How could i do it

```\$8 = InputBox("Step 8-", "", "What will fast tp key be?", "5", -1, -1, 0, 0)
For \$8 = 1 To \$8
\$k=\$k+1
\$8_\$k=InputBox("Step "&\$k&"-"&\$8, "","The "&\$k&"of "&\$8&"Message", "Tp Up", -1, -1, 0, 0)
Next```

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Havent tested yet but im shur it wont work

I need it to make \$8 to add like so each one \$8_1,\$8_2,\$8_3

How could i do it

```\$8 = InputBox("Step 8-", "", "What will fast tp key be?", "5", -1, -1, 0, 0)
For \$8 = 1 To \$8
\$k=\$k+1
\$8_\$k=InputBox("Step "&\$k&"-"&\$8, "","The "&\$k&"of "&\$8&"Message", "Tp Up", -1, -1, 0, 0)
Next```
I have NO IDEA what you're trying to do, but I tried to set variables with Eval():

```\$8 = 'A'
\$k=1
Eval(\$8 & "_" & \$k) = 'Test'
MsgBox(64, "Results", "\$A_1 = " & \$A_1)```

Doesn't work. I'm not sure you can specify a variable with a variable. How about an array instead?

```#include <array.au3>

\$Count = InputBox("Input", "How many values for the table?")
If Not StringIsInt(\$Count) Or \$Count < 1 Then
MsgBox(16, "Error", "Value must be a positive integer!")
Exit
EndIf

Dim \$8[\$Count + 1]
\$8[0] = \$Count

For \$k = 1 To \$Count
\$8[\$k] = InputBox("Input", "Input value for table index " & \$k & ":")
Next

_ArrayDisplay(\$8, "Resulting array:")```

Hope that helps!

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