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Posted

I have a script that looks at a file share to see if a new version of the script exists. What I would like to and have not found a method is to then copy it over the one that is executing. I tried using;

FileCopy ( "\\share\updates\sample.exe", @WorkingDir, 1)

while executing sample.exe from a login script. FileCopy returns "0" indicating failure.

Any thougts would be appreciated!

Posted

Hi,

I dunno whether that is possible, but what about copying it, save it with another name. Start it, stop the first one, delete it, rename itself.

So long,

Mega

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Posted

Hi,

I dunno whether that is possible, but what about copying it, save it with another name. Start it, stop the first one, delete it, rename itself.

So long,

Mega

how to? for my application auto update

thanx

Posted

Try this:

$newexe = "\\share\updates\sample.exe"
$myver = FileGetTime (@ScriptFullPath , 0, 1 )
$newver = FileGetTime ($newexe , 0, 1 )

if $newver > $myver Then
    FileCopy ($newexe, @WorkingDir&"\sample-new.exe", 1)
    run($newexe, @WorkingDir)
    Exit
EndIf

if @ScriptFullPath = @WorkingDir&"\sample-new.exe" Then
    FileCopy (@ScriptFullPath, @WorkingDir&"\sample.exe", 1)
    run(@WorkingDir&"\sample.exe",@WorkingDir)
    Exit
EndIf

[font="Fixedsys"][list][*]All of my AutoIt Example Scripts[*]http://saneasylum.com[/list][/font]

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