Autoit Math

[HackerZer0]

i'm in 9th grade Algebra II... and i was trying to make a script that calculates the 'zeros' of a quadratic equation, but i couldn't figure it out, and i kept getting floating point numbers when i know they should be natural numbers...can someone help me?

for reference listed below are the things you'd need to make it...

x represents the value we need to find, the 'zero'...

formula:

x = {-b + (b - 4*a*c) ^ (1/2)} / 2a

and

x = {-b - (b - 4*a*c) ^ (1/2)} / 2a

i want it to ask for the values of a, b, and c and give the solution... plz help

[martin]

i'm in 9th grade Algebra II... and i was trying to make a script that calculates the 'zeros' of a quadratic equation, but i couldn't figure it out, and i kept getting floating point numbers when i know they should be natural numbers...can someone help me?

for reference listed below are the things you'd need to make it...

x represents the value we need to find, the 'zero'...

formula:

x = {-b + (b - 4*a*c) ^ (1/2)} / 2a

and

x = {-b - (b - 4*a*c) ^ (1/2)} / 2a

i want it to ask for the values of a, b, and c and give the solution... plz help

doesn't a stright calculation like below work?

$a = 2

$b=24

$c=1

$x1 = (-$b + Sqrt($b-4*$a*$c))/(2*$a)

$x2 = (-$b - Sqrt($b-4*$a*$c))/(2*$a)

msgbox(0,$x1,$x2)

[mikehunt114]

I believe you have the quadratic formula wrong.

$x1 = (-$b + Sqrt(($b^2)-4*$a*$c))/(2*$a)

Edited December 2, 2006 by mikehunt114

[Paulie]

I made this once before, but before i posted it in the examples, i searched to see if one had already been posted, It appeared one had been posted, so i use that one now since its better then mine

Func _Quadratic($_A, $_B, $_C, $_Acc=3)
    Local $_Result[2]
    Local $_NegB = $_B*-1, $_Top1 = ($_NegB - Sqrt((($_B^2)-(4*$_A*$_C)))), _
    $_Top2 = ($_NegB + Sqrt((($_B^2)-(4*$_A*$_C)))), $_Bottom = (2*$_A)
    $_Result[0] = Round($_Top1/$_Bottom, $_Acc)
    $_Result[1] = Round($_Top2/$_Bottom, $_Acc)
    Return $_Result
EndFunc

Can't remember the original author, but a simple title search for "Quadratic" should turn it up.

[HackerZer0]

I believe you have the quadratic formula wrong.

$x1 = (-$b + Sqrt(($b^2)-4*$a*$c))/(2*$a)

oh, yup thanks... comforting to know it wasn't my code that was the problem, but careless typing... thx

: )