Can AutoIT Dynamically build the Function Name?

[PerryRaptor]

Can AutoIT generate the name of a function? I have about a dozen functions that I want to call via one IF...EndIf loop nested inside a While...Wend loop.

CommandArray[x]

If XXXX == CommandArray[$get_x] then

$FunctionName = "Function" & $get_x & "()"

Sleep(1000)

ContinueLoop

EndIf

Func Function1()

.......................

EndFunc

Func Function2()

........................

EndFunc

[SmOke_N]

Have you looked at Call()?

[PerryRaptor]

Just now I looked at Call() and I don't see how that will work. I had difficulty following the help file instructions and examples.

[BALA]

Just now I looked at Call() and I don't see how that will work. I had difficulty following the help file instructions and examples.

That sounds a bit oxymoronic...

Anyways, I don't think Call() can be used to find the function's name, since it requires the function's name to work.

[PerryRaptor]

Easy...I'm from the planet OxyMoronIC

The helpfile didn't make sense as a means to my desire.

[BALA]

Easy...I'm from the planet OxyMoronIC

The helpfile didn't make sense as a means to my desire.

Hence to what I said in my second paragraph/sentence:

Anyways, I don't think Call() can be used to find the function's name, since it requires the function's name to work.

There's probably another command that can be used. I sometimes also despise the help file's "vagueness"

Edited January 27, 2007 by BALA

[Helge]

I'm not sure who's confused; if it's you or me, but you could please explain what you mean with

the word "generate" ? Do you want to run a function, named by mixing strings and variables or

is it something else ?

Maybe something like this...

$i = 2
Call("Function" & $i)

If you're confused by how Call works, then this points out what I said about it earlier today or

yesterday...

[PerryRaptor]

It is against the doctrine of planet OxyMoronIC to complain about AutoIT because it is free.

[PerryRaptor]

@Helge...

I read your post regarding Call() too...I'd like to learn more about the command because your post leads me to believe there is more than can be done with it.

I want the IF...EndIF to create the name of the function that matches the one in the CommandArray. After creating the FunctionName, e.g. Function7() execute it.

[BALA]

$get_x = 1
While 1
    $FunctionName = "Function" & $get_x & "()"
    Call($FunctionName)
    $get_x = $get_x + 1
    If $get_x = 12
        ExitLoop
    EndIf
WEnd

Would that do it?

[PerryRaptor]

@Bala...

Doesn't work

[BALA]

Maybe if you change the "&"s to "+"s

The theory is that it will set "Function1()" for $FunctionName and put that in the Call(). Then it will loop changing it 1 higher, so now "Function2()", and it'll do that until Function12().

Perhaps Call() doesn't work with the "()"

Another option is to just take out the "Call()" part completely and leave it as:

$get_x = 1
While 1
    $FunctionName = "Function" & $get_x & "()"
    $FunctionName
    $get_x = $get_x + 1
    If $get_x = 12
        ExitLoop
    EndIf
WEnd

Edited January 27, 2007 by BALA

[PerryRaptor]

This works...I didn't need the "()" at the end when generating/creating the function name.

$get_x = "One"
While 1
    $FunctionName = "Function" & $get_x
    Sleep(1000)
    Call($FunctionName)
WEnd

Func FunctionOne()
    MsgBox(0,"Function One", "this is Function #1")
EndFunc

Thanks everyone

[Xenobiologist]

Hi,

For $i = 0 To 2
    Call("_do" & $i)
Next

Func _do0()
    ConsoleWrite(0 & @CRLF)
EndFunc
Func _do1()
    ConsoleWrite(1 & @CRLF)
EndFunc
Func _do2()
    ConsoleWrite(2 & @CRLF)
EndFunc

So long,

Mega

[SmOke_N]

From:

Anyways, I don't think Call() can be used to find the function's name, since it requires the function's name to work.

To:

Maybe if you change the "&"s to "+"s

The theory is that it will set "Function1()" for $FunctionName and put that in the Call(). Then it will loop changing it 1 higher, so now "Function2()", and it'll do that until Function12().

Perhaps Call() doesn't work with the "()"

Another option is to just take out the "Call()" part completely and leave it as:

$get_x = 1
While 1
    $FunctionName = "Function" & $get_x & "()"
    $FunctionName
    $get_x = $get_x + 1
    If $get_x = 12
        ExitLoop
    EndIf
WEnd

Hmmm...

[BALA]

From:

To:

Hmmm...

I misunderstood what the question the first time until it was clarified in a later post, it happens.