qwertylol Posted June 1, 2007 Posted June 1, 2007 4.9.1.2.3.3.4.0.0.4.2.3.4.9.8.4.0.0.0.0.4.2.3.4.9.0.0.0.2.3.8.3.2. how do I add the numbers above together? exp, a shorter version: 4.9.1.2.3.3 the sum is 22.
jefhal Posted June 1, 2007 Posted June 1, 2007 (edited) $var = "4.9.1.2.3.3.4.0.0.4.2.3.4.9.8.4.0.0.0.0.4.2.3.4.9.0.0.0.2.3.8.3.2" $out = StringReplace($var,".","+") If StringRight($out,1) = "+" Then $out = StringLeft($out,StringInStr($out,"+",0,-1)-1) EndIf MsgBox(1,"$out",$out) $sum = Execute($out) MsgBox(1,"$sum",$sum) Edited June 1, 2007 by jefhal ...by the way, it's pronounced: "JIF"... Bob Berry --- inventor of the GIF format
1905russell Posted June 1, 2007 Posted June 1, 2007 4.9.1.2.3.3.4.0.0.4.2.3.4.9.8.4.0.0.0.0.4.2.3.4.9.0.0.0.2.3.8.3.2. how do I add the numbers above together? exp, a shorter version: 4.9.1.2.3.3 the sum is 22.This is the simplest way $iSum =(4+9+1+2+3+3) msgbox(0,"",$iSum)
qwertylol Posted June 1, 2007 Author Posted June 1, 2007 This is the simplest way $iSum =(4+9+1+2+3+3) msgbox(0,"",$iSum) AHAHAHAHAHAAHA no, please try again, with automatic addition this time
1905russell Posted June 1, 2007 Posted June 1, 2007 AHAHAHAHAHAAHA no, please try again, with automatic addition this time How about $iSum = Stringsplit("4.9.1.2.3.3",".") $iTot = 0 For $icount = 1 to $iSum[0] $iTot += $iSum[$icount] next msgbox(0,"",$iTot)
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